如何从此 python 代码中删除多余的逗号

Question

这是我的 python 代码，最后给了我一个额外的逗号，我无法弄清楚如何解决这个问题。

代码：

x = int(input())
y = int(input())
z = int(input())
n = int(input())
print("[",end="")
for i in range(0,x+1):
    for j in range(0,y+1):
        for k in range(0,z+1):
            if((i+j+k)!=n):
                print("[",end="")
                print(i,end=",")
                print(j,end=",")
                print(k,end="")
                print("]",end="")
                print("",end=",")
print("]",end="")

Output

Answer 1

您可以使用join方法：

x = int(input())
y = int(input())
z = int(input())
n = int(input())

print("[", end="")
join_list = []
for i in range(0, x + 1):
    for j in range(0, y + 1):
        for k in range(0, z + 1):
            if (i + j + k) != n:
                join_list.append(f"[{i},{j},{k}]")
print(",".join(join_list), end="")
print("]", end="")

或结合理解：

x = int(input())
y = int(input())
z = int(input())
n = int(input())

print(
    "["
    + ",".join(
        f"[{i},{j},{k}]"
        for i in range(x + 1) for j in range(y + 1) for k in range(z + 1)
        if i + j + k != n
    )
    + "]",
    end=""
)

或者使用itertools.product而不是嵌套推导：

from itertools import product

x = int(input())
y = int(input())
z = int(input())
n = int(input())

print(
    "["
    + ",".join(
        "[{},{},{}]".format(*p)
        for p in product(range(x + 1), range(y + 1), range(z + 1))
        if sum(p) != n
    )
    + "]",
    end=""
)

或者先构建列表，然后将其转换为字符串并替换空格：

from itertools import product

x = int(input())
y = int(input())
z = int(input())
n = int(input())

result = [
    list(p)
    for p in product(range(x + 1), range(y + 1), range(z + 1))
    if sum(p) != n
]
print(str(result).replace(" ", ""), end="")

Answer 2

append func 用于收集

y = int(input())
z = int(input())
n = int(input())
a =  []
# print("[",end="")
for i in range(0,x+1):
    for j in range(0,y+1):
        for k in range(0,z+1):
            if((i+j+k)!=n):
                a.append([i,j,k])
print(a)