[英]Filter rows based on condition in Pandas
我有 dataframe df_groups 包含样本号、组号和精度。
Tabel 1: Samples with their groups
+----+----------+------------+------------+
| | sample | group | Accuracy |
|----+----------+------------+------------|
| 0 | 0 | 6 | 91.6 |
| 1 | 1 | 4 | 92.9333 |
| 2 | 2 | 2 | 91 |
| 3 | 3 | 2 | 90.0667 |
| 4 | 4 | 4 | 91.8 |
| 5 | 5 | 5 | 92.5667 |
| 6 | 6 | 6 | 91.1 |
| 7 | 7 | 5 | 92.3333 |
| 8 | 8 | 2 | 92.7667 |
| 9 | 9 | 0 | 91.1333 |
| 10 | 10 | 4 | 92.5 |
| 11 | 11 | 5 | 92.4 |
| 12 | 12 | 7 | 93.1333 |
| 13 | 13 | 7 | 93.5333 |
| 14 | 14 | 2 | 92.1 |
| 15 | 15 | 6 | 93.2 |
| 16 | 16 | 8 | 92.7333 |
| 17 | 17 | 8 | 90.8 |
| 18 | 18 | 3 | 91.9 |
| 19 | 19 | 3 | 93.3 |
| 20 | 20 | 5 | 90.6333 |
| 21 | 21 | 9 | 92.9333 |
| 22 | 22 | 4 | 93.3333 |
| 23 | 23 | 9 | 91.5333 |
| 24 | 24 | 9 | 92.9333 |
| 25 | 25 | 1 | 92.3 |
| 26 | 26 | 9 | 92.2333 |
| 27 | 27 | 6 | 91.9333 |
| 28 | 28 | 5 | 92.1 |
| 29 | 29 | 8 | 84.8 |
+----+----------+------------+------------+
我想返回具有以上任何精度(例如 92)的 dataframe。 所以结果会是这样的
Tabel 1: Samples with their groups when accuracy above 92.
+----+----------+------------+------------+
| | sample | group | Accuracy |
|----+----------+------------+------------|
| 1 | 1 | 4 | 92.9333 |
| 2 | 5 | 5 | 92.5667 |
| 3 | 7 | 5 | 92.3333 |
| 4 | 8 | 2 | 92.7667 |
| 5 | 10 | 4 | 92.5 |
| 6 | 11 | 5 | 92.4 |
| 7 | 12 | 7 | 93.1333 |
| 8 | 13 | 7 | 93.5333 |
| 9 | 14 | 2 | 92.1 |
| 10 | 15 | 6 | 93.2 |
| 11 | 16 | 8 | 92.7333 |
| 12 | 19 | 3 | 93.3 |
| 13 | 21 | 9 | 92.9333 |
| 14 | 22 | 4 | 93.3333 |
| 15 | 24 | 9 | 92.9333 |
| 16 | 25 | 1 | 92.3 |
| 17 | 26 | 9 | 92.2333 |
| 18 | 28 | 5 | 92.1 |
+----+----------+------------+------------+
因此,结果将根据大于或等于预定义精度(例如 92、90 或 85 等)的条件返回。
您可以使用df.loc[df['Accuracy'] >= predefined_accuracy]
。
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