python for 循环仅返回第一个索引项

Question

正如标题所说的一切，我也查看了一些stackoverflow相同的问题，但我无法找到解决方案这是我的代码

r = requests.get("http://cpaleaks.com", headers={'User-agent': 'Mozilla/5.0 (X11; Ubuntu; 
Linux x86_64; rv:61.0) Gecko/20100101 Firefox/61.0'})
c = r.content
soup = BeautifulSoup(c,"html.parser")

all = soup.find_all("div",{"id":"content"})

all[0].find_all("h2")[0].text

for item in all:
    print(item.find_all("h2")[0].text)

Output

6 Untapped Traffic Sources in 2019 That Convert With ANY Niche

预计 Output

必须是网站的所有标题

Answer 1

怎么了？

find_all("div",{"id":"content"})将为您提供一个<div>及其内部元素树的结果集，因此您只迭代一次并仅打印一次文本第一个<h2>

print(item.find_all("h2")[0].text)

怎么修？

在find_all('h2')时迭代结果集中的第一个元素：

for item in all[0].find_all("h2")
    print(item.text)

或者在我看来更具体和更清洁的解决方案，迭代所有<h2>元素（div）中具有 id 内容的选择：

for item in soup.select('#content h2'):
    print(item.text.strip())

例子

import requests
from bs4 import BeautifulSoup
import pandas as pd
r = requests.get("http://cpaleaks.com", headers={'User-agent': 'Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:61.0) Gecko/20100101 Firefox/61.0'})
c = r.content
soup = BeautifulSoup(c,"html.parser")

for item in soup.select('#content h2'):
    print(item.text.strip())

Output

6 Untapped Traffic Sources in 2019 That Convert With ANY Niche
3 SECRET Steps to Make Money on Instagram WITHOUT Followers – Fast & Efficient
Facebook Marketing in 2019 – SMART Strategies + Case Study!
Rank Local Businesses on the FIRST page of Google – Profit from NOOBS like a PRO!
Reddit is STILL Endless Source Of FREE Marketing Traffic – IF DONE RIGHT!
How To EXPLODE Your Earnings With HOT Targeted Pins on Pinterest
The Key In the LIST! Grow Your Subscriber Count Super FAST – Build Your Money Making MACHINE!
How to Monetize Virtual Businesses on Groupon and Make Up To $100K THIS YEAR
Laser Targeted Quora Strategy to Profit With Clickbank Products – QUORA DONE RIGHT!

Answer 2

我不确定 beautifulsoup 是如何工作的，但也许可以尝试使用此代码而不是最后的 for。

for h2 in all[0].find_all("h2")
    print(h2.text)