Skip 2 Index 在for循环体中，Python VS C++

Question

在下面的第一个代码中（使用 for 循环）当我想通过增加 for 循环体内的索引来跳过 2 索引时，它会忽略i = i+2并仅使用for i in range (len(c))短语，而在 c++ 中，我们可以通过for (int i = 0; i <sizeof(c);i++){i += 2;}在 for 循环体中执行此操作。 无论如何使用for循环（通过更正第一个代码）来实现这个还是我必须使用一个while循环（第二个代码）？

第一个代码（For循环）

def jumpingOnClouds(c):

    count_jumps = 0 
    
    for i in range (len(c)):       

        if (i+2 <len(c) and c[i] == 0 and c[i+2] ==0):
            i = i+2
            count_jumps+=1#It doesnt let me to update i in the while loop
            
        elif (i+1 <len(c) and c[i] == 0 and c[i+1] ==0):
            
            count_jumps+=1
        
        else:
            pass    
        
    return(count_jumps)
  
c = [0, 0, 0, 1, 0, 0]
   
jumpingOnClouds(c)

第二个代码（While 循环）

def jumpingOnClouds(c):

    count_jumps = 0 
    
    i = 0
    
    while( i < len(c)):       

        if (i+2 <len(c) and c[i] == 0 and c[i+2] ==0):
            i = i+2
            count_jumps+=1
            
        elif (i+1 <len(c) and c[i] == 0 and c[i+1] ==0):
            
            count_jumps+=1
            i = i+1
        
        else:
            i = i+1   
        
    return(count_jumps)
c = [0, 0, 0, 1, 0, 0]
   
jumpingOnClouds(c)

Answer 1

您可以使用continue跳过。 您只需要一个条件为True 。

def jumpingOnClouds(c):
    skipCondition = False
    count_jumps = 0 
    
    for i in range (len(c)):       
        if skipCondition:
            skipCondition = False
            continue
        if (i+2 <len(c) and c[i] == 0 and c[i+2] ==0):
            count_jumps+=1#It doesnt let me to update i in the while loop
            skipCondition = True
            continue
            
        elif (i+1 <len(c) and c[i] == 0 and c[i+1] ==0):
            
            count_jumps+=1
        
        else:
            pass    
        
    return(count_jumps)
  
c = [0, 0, 0, 1, 0, 0]
   
jumpingOnClouds(c)

放置continue将继续迭代，但在此之前，它会使skipCondition = True 。 下一次迭代， skipCondition将为True ，因此您将再次跳过，但将skipCondition设置回False