读取来自.csv 的 URL 列表，用于使用 Python、BeautifulSoup、Z251D2BBFE9A3B95EAZCE5696 进行抓取

Question

This was part of another question (see Reading URLs from.csv and appending scrape results below previous with Python, BeautifulSoup, Pandas ) which was generously answered by @HedgeHog and contributed to by @QHarr.

在下面的代码中，我只是将 3 个示例源 URL 粘贴到代码中。 但是我有一长串要抓取的 URL（1000+），它们存储在 a.csv 文件的第一列（我们称之为“urllist.csv”）。 我宁愿从那个文件中读取。

我想我知道“打开时”的基本结构，但我在如何将其链接到代码的 rest 时遇到问题。 您的帮助将不胜感激。

import requests
from bs4 import BeautifulSoup
import pandas as pd

urls = ['https://www.marketresearch.com/Infiniti-Research-Limited-v2680/Global-Induction-Hobs-30196623/',
        'https://www.marketresearch.com/Infiniti-Research-Limited-v2680/Global-Human-Capital-Management-30196628/',
        'https://www.marketresearch.com/Infiniti-Research-Limited-v2680/Global-Probe-Card-30196643/']
data = []

for url in urls:
    page = requests.get(url)
    soup = BeautifulSoup(page.text, 'html.parser')
    toc = soup.find("div", id="toc")


    def get_drivers():
        data.append({
            'url': url,
            'type': 'driver',
            'list': [x.get_text(strip=True) for x in toc.select('li:-soup-contains-own("Market drivers") li')]
        })


    get_drivers()


    def get_challenges():
        data.append({
            'url': url,
            'type': 'challenges',
            'list': [x.get_text(strip=True) for x in toc.select('li:-soup-contains-own("Market challenges") ul li') if
                     'Table Impact of drivers and challenges' not in x.get_text(strip=True)]
        })


    get_challenges()

pd.concat([pd.DataFrame(data)[['url', 'type']], pd.DataFrame(pd.DataFrame(data).list.tolist())],
          axis=1).to_csv('output.csv')

Answer 1

由于您使用的是 pandas， read_csv将为您解决问题： https://pandas.pydata.org/docs/reference/api/pandas.read_csv.ZFC35FDC70D5FC69D2698ZA822E

如果你想自己写，你可以使用内置的 csv 库

with open('urls.csv', newline='') as csvfile:
    reader = csv.DictReader(csvfile)
    for row in reader:
        print(row["url"])