查找从一个列表到另一个列表的项目的差异

Question

我有一个包含以下向量值的列表

list1 = [[-27.1785, -20.7318, -40.724]]
list2 = [[-27.1785, -20.7318, -40.724], [-27.1786, -20.7318, -40.724], [27.1786, -20.7318, -40.724]]

如您所见， list2中的索引 0 和 1 在list1中，但我无法解决如何在 list2 上找到 list1 中的向量值，然后打印出不同的向量值应该是[27.1786, -20.7318, -40.724] 。

Answer 1

l1 =  [[-27.1785, -20.7318, -40.724]]
l2 = [[-27.1785, -20.7318, -40.724], [-27.1786, -20.7318, -40.724], [-27.1786, -20.7318, -40.724]]

z = [x for x in l2 if x not in l1]
b_set = set(map(tuple,z))
b = list(map(list,b_set))
print(b)