如果 object 包含在 javascript 的对象数组中，如何检查整个原始 object（不使用任何属性）？

Question

我想用对象数组检查整个原始 object。 我不想使用任何属性名称进行比较。

 const items = [{ a: 1 },{ a: 2 },{ a: 3 }];
  const item1 = { a: 2 };
  

如果我想检查item1是否存在于items数组中而不使用任何属性但使用
整个 object。
indexOf filter some甚至lopping在这种情况下不起作用。
在这方面需要帮助。 如何检查？
顺便说一句，我的情况不同。 我有一个很长的 object 并且它的唯一性取决于许多属性，这就是为什么我不想使用属性进行比较。

我有这样的东西。

function bigArraySol() {
  const bigArray = [
    {
      product_id: "1",
      product_name: "Womens Achara",
      total_price: "8000",
      unique_product_id: "1",
      seller_id: "sell1",
      image: "https://i.imgur.com/6CsDtqD.jpg",
      quantity: 3,
      product_types: [
        {
          product_type_id: "1",
          product_type_name: "Achara Cloth",
          attributes: [
            {
              attribute_name: "Achara Length",
              attribute_value: "4"
            },
            {
              attribute_name: "Achara Cloth",
              attribute_value: "Terry Cotton"
            }
          ]
        },
        {
          product_type_id: "2",
          product_type_name: "Khadki ",
          attributes: [
            {
              attribute_name: "Khadki Cloth",
              attribute_value: "Ready Made"
            },
            {
              attribute_name: "khadki Color",
              attribute_value: "mix"
            }
          ]
        },
        {
          product_type_id: "3",
          product_type_name: "Blouse",
          attributes: [
            {
              attribute_name: "Blouse Size",
              attribute_value: "20"
            }
          ]
        }
      ]
    },
    {
      product_id: "1",
      product_name: "Womens Achara",
      total_price: "8000",
      unique_product_id: "1",
      seller_id: "sell1",
      image: "https://i.imgur.com/6CsDtqD.jpg",
      quantity: 3,
      product_types: [
        {
          product_type_id: "1",
          product_type_name: "Achara Cloth",
          attributes: [
            {
              attribute_name: "Achara Length",
              attribute_value: "4"
            },
            {
              attribute_name: "Achara Cloth",
              attribute_value: "Terry Cotton"
            }
          ]
        },
        {
          product_type_id: "2",
          product_type_name: "Khadki ",
          attributes: [
            {
              attribute_name: "Khadki Cloth",
              attribute_value: "Ready Made"
            },
            {
              attribute_name: "khadki Color",
              attribute_value: "mix"
            }
          ]
        },
        {
          product_type_id: "3",
          product_type_name: "Blouse",
          attributes: [
            {
              attribute_name: "Blouse Size",
              attribute_value: "25"
            }
          ]
        }
      ]
    },
    {
      product_id: "1",
      product_name: "Womens Achara",
      total_price: "8000",
      unique_product_id: "1",
      seller_id: "sell1",
      image: "https://i.imgur.com/6CsDtqD.jpg",
      quantity: 3,
      product_types: [
        {
          product_type_id: "1",
          product_type_name: "Achara Cloth",
          attributes: [
            {
              attribute_name: "Achara Length",
              attribute_value: "4"
            },
            {
              attribute_name: "Achara Cloth",
              attribute_value: "Terry Cotton"
            }
          ]
        },
        {
          product_type_id: "2",
          product_type_name: "Khadki ",
          attributes: [
            {
              attribute_name: "Khadki Cloth",
              attribute_value: "Ready Made"
            },
            {
              attribute_name: "khadki Color",
              attribute_value: "mix"
            }
          ]
        },
        {
          product_type_id: "3",
          product_type_name: "Blouse",
          attributes: [
            {
              attribute_name: "Blouse Size",
              attribute_value: "25"
            }
          ]
        }
      ]
    }
  ];

  const compairingObj = {
    product_id: "1",
    product_name: "Womens Achara",
    total_price: "8000",
    unique_product_id: "1",
    seller_id: "sell1",
    image: "https://i.imgur.com/6CsDtqD.jpg",
    quantity: 3,
    product_types: [
      {
        product_type_id: "1",
        product_type_name: "Achara Cloth",
        attributes: [
          {
            attribute_name: "Achara Length",
            attribute_value: "4"
          },
          {
            attribute_name: "Achara Cloth",
            attribute_value: "Terry Cotton"
          }
        ]
      },
      {
        product_type_id: "2",
        product_type_name: "Khadki ",
        attributes: [
          {
            attribute_name: "Khadki Cloth",
            attribute_value: "Ready Made"
          },
          {
            attribute_name: "khadki Color",
            attribute_value: "mix"
          }
        ]
      },
      {
        product_type_id: "3",
        product_type_name: "Blouse",
        attributes: [
          {
            attribute_name: "Blouse Size",
            attribute_value: "20"
          }
        ]
      }
    ]
  };
}

在沙箱中查看： https://codesandbox.io/s/javascript-forked-q8yu6?file=/index.js:0-4933

Answer 1

您可以简单地 JSON 将它们字符串化并进行比较。

 const items = [{ a: 1 },{ a: 2 },{ a: 3 }]; const item1 = { a: 2 }; items.map((item, index) => { if (JSON.stringify(item) === JSON.stringify(item1)) { console.log('item1 exists in index ' + index); } })

Answer 2

此代码使用循环并查看属性来实现“数组中的对象 indexOf”。 它非常简单，并且将匹配haystack中的任何 object，它对于needle object 的每个属性具有相同的值。 应该很容易修改以检查匹配项是否没有在针中找不到的属性 - 但我不确定您的需求。

 const indexOf = (needle, haystack) => { let index = -1; haystack.every((o,i) => { let found = true; for (let [k,v] of Object.entries(needle)) { if (o[k];== v) { found = false; break; } } if (found) index=i; return;found; // false exits }): return index, } const haystack = [{ a: 1 },{ a: 2 };{ a: 3 }]; const needle = { a. 2 }, console;log(indexOf(needle, haystack)); // returns 1