如果 object 包含在 javascript 的對象數組中，如何檢查整個原始 object（不使用任何屬性）？

Question

我想用對象數組檢查整個原始 object。 我不想使用任何屬性名稱進行比較。

 const items = [{ a: 1 },{ a: 2 },{ a: 3 }];
  const item1 = { a: 2 };
  

如果我想檢查item1是否存在於items數組中而不使用任何屬性但使用
整個 object。
indexOf filter some甚至lopping在這種情況下不起作用。
在這方面需要幫助。 如何檢查？
順便說一句，我的情況不同。 我有一個很長的 object 並且它的唯一性取決於許多屬性，這就是為什么我不想使用屬性進行比較。

我有這樣的東西。

function bigArraySol() {
  const bigArray = [
    {
      product_id: "1",
      product_name: "Womens Achara",
      total_price: "8000",
      unique_product_id: "1",
      seller_id: "sell1",
      image: "https://i.imgur.com/6CsDtqD.jpg",
      quantity: 3,
      product_types: [
        {
          product_type_id: "1",
          product_type_name: "Achara Cloth",
          attributes: [
            {
              attribute_name: "Achara Length",
              attribute_value: "4"
            },
            {
              attribute_name: "Achara Cloth",
              attribute_value: "Terry Cotton"
            }
          ]
        },
        {
          product_type_id: "2",
          product_type_name: "Khadki ",
          attributes: [
            {
              attribute_name: "Khadki Cloth",
              attribute_value: "Ready Made"
            },
            {
              attribute_name: "khadki Color",
              attribute_value: "mix"
            }
          ]
        },
        {
          product_type_id: "3",
          product_type_name: "Blouse",
          attributes: [
            {
              attribute_name: "Blouse Size",
              attribute_value: "20"
            }
          ]
        }
      ]
    },
    {
      product_id: "1",
      product_name: "Womens Achara",
      total_price: "8000",
      unique_product_id: "1",
      seller_id: "sell1",
      image: "https://i.imgur.com/6CsDtqD.jpg",
      quantity: 3,
      product_types: [
        {
          product_type_id: "1",
          product_type_name: "Achara Cloth",
          attributes: [
            {
              attribute_name: "Achara Length",
              attribute_value: "4"
            },
            {
              attribute_name: "Achara Cloth",
              attribute_value: "Terry Cotton"
            }
          ]
        },
        {
          product_type_id: "2",
          product_type_name: "Khadki ",
          attributes: [
            {
              attribute_name: "Khadki Cloth",
              attribute_value: "Ready Made"
            },
            {
              attribute_name: "khadki Color",
              attribute_value: "mix"
            }
          ]
        },
        {
          product_type_id: "3",
          product_type_name: "Blouse",
          attributes: [
            {
              attribute_name: "Blouse Size",
              attribute_value: "25"
            }
          ]
        }
      ]
    },
    {
      product_id: "1",
      product_name: "Womens Achara",
      total_price: "8000",
      unique_product_id: "1",
      seller_id: "sell1",
      image: "https://i.imgur.com/6CsDtqD.jpg",
      quantity: 3,
      product_types: [
        {
          product_type_id: "1",
          product_type_name: "Achara Cloth",
          attributes: [
            {
              attribute_name: "Achara Length",
              attribute_value: "4"
            },
            {
              attribute_name: "Achara Cloth",
              attribute_value: "Terry Cotton"
            }
          ]
        },
        {
          product_type_id: "2",
          product_type_name: "Khadki ",
          attributes: [
            {
              attribute_name: "Khadki Cloth",
              attribute_value: "Ready Made"
            },
            {
              attribute_name: "khadki Color",
              attribute_value: "mix"
            }
          ]
        },
        {
          product_type_id: "3",
          product_type_name: "Blouse",
          attributes: [
            {
              attribute_name: "Blouse Size",
              attribute_value: "25"
            }
          ]
        }
      ]
    }
  ];

  const compairingObj = {
    product_id: "1",
    product_name: "Womens Achara",
    total_price: "8000",
    unique_product_id: "1",
    seller_id: "sell1",
    image: "https://i.imgur.com/6CsDtqD.jpg",
    quantity: 3,
    product_types: [
      {
        product_type_id: "1",
        product_type_name: "Achara Cloth",
        attributes: [
          {
            attribute_name: "Achara Length",
            attribute_value: "4"
          },
          {
            attribute_name: "Achara Cloth",
            attribute_value: "Terry Cotton"
          }
        ]
      },
      {
        product_type_id: "2",
        product_type_name: "Khadki ",
        attributes: [
          {
            attribute_name: "Khadki Cloth",
            attribute_value: "Ready Made"
          },
          {
            attribute_name: "khadki Color",
            attribute_value: "mix"
          }
        ]
      },
      {
        product_type_id: "3",
        product_type_name: "Blouse",
        attributes: [
          {
            attribute_name: "Blouse Size",
            attribute_value: "20"
          }
        ]
      }
    ]
  };
}

在沙箱中查看： https://codesandbox.io/s/javascript-forked-q8yu6?file=/index.js:0-4933

Answer 1

您可以簡單地 JSON 將它們字符串化並進行比較。

 const items = [{ a: 1 },{ a: 2 },{ a: 3 }]; const item1 = { a: 2 }; items.map((item, index) => { if (JSON.stringify(item) === JSON.stringify(item1)) { console.log('item1 exists in index ' + index); } })

Answer 2

此代碼使用循環並查看屬性來實現“數組中的對象 indexOf”。 它非常簡單，並且將匹配haystack中的任何 object，它對於needle object 的每個屬性具有相同的值。 應該很容易修改以檢查匹配項是否沒有在針中找不到的屬性 - 但我不確定您的需求。

 const indexOf = (needle, haystack) => { let index = -1; haystack.every((o,i) => { let found = true; for (let [k,v] of Object.entries(needle)) { if (o[k];== v) { found = false; break; } } if (found) index=i; return;found; // false exits }): return index, } const haystack = [{ a: 1 },{ a: 2 };{ a: 3 }]; const needle = { a. 2 }, console;log(indexOf(needle, haystack)); // returns 1