[英]How to authenticate http request, for accessing gcp API services (python)
为了获得启用的 GCP-api 服务列表,我试图根据此链接中的 HTTP 请求获取 service.list。
这是我的代码:
import json
from requests.auth import HTTPBasicAuth
import requests
from google.oauth2 import service_account
auth = HTTPBasicAuth('myusername@gmail.com','xyz....')
url = 'https://serviceusage.googleapis.com/v1/projects/my-proj-id123/services'
headers = {
"Accept": "application/json"
}
response = requests.request(
"GET",
url,
headers=headers,
auth=auth
)
# a=json.loads(response.text)
print(response.text)
但我收到此错误:
{
"error": {
"code": 403,
"message": "The request is missing a valid API key.",
"status": "PERMISSION_DENIED"
}
}
注意:我需要通过服务帐户或api 令牌来根据此链接获取响应。 我有服务帐户密钥( credential.json
),但我不知道将 http 请求放在哪里。 请建议我的程序。
我鼓励您在与 Google 的服务交互时考虑使用 Google 的 SDK。
这些服务不仅提供有助于创建请求和响应的特定于语言的资源类型,而且您可以获得更简单的身份验证、日志记录等。
记录在案:
ListServicesPager
--> ListServicesResponse
--> ManagedService
services.list
--> 响应--> ManagedService设置:
PROJECT=[[YOUR-PROJECT]]
ACCOUNT=[[YOUR-ACCOUNT]]
python3 -m venv venv
source venv/bin/activate
python3 -m pip install google-auth
python3 -m pip install google-cloud-service-management
gcloud iam service-accounts create ${ACCOUNT} \
--project=${PROJECT}
EMAIL="${ACCOUNT}@${PROJECT}.iam.gserviceaccount.com"
gcloud projects add-iam-policy-binding ${PROJECT} \
--member=serviceAccount:${EMAIL} \
--role=roles/viewer
gcloud iam service-accounts keys create ${PWD}/${ACCOUNT}.json \
--iam-account=${EMAIL}
export GOOGLE_APPLICATION_CREDENTIALS=${PWD}/${ACCOUNT}.json
python3 ./main.py
main.py
:
import google.auth
from google.cloud import servicemanagement_v1
credentials,project = google.auth.default()
client = servicemanagement_v1.ServiceManagerClient()
# How to construct the Request
rqst = {
"pageSize": 5 # Purely for example
}
# Response is a ServiceListPager
resp = client.list_services(request=rqst)
# Which is iterable
for managed_service in resp:
try:
# This is a quirk of gRPC Transcoding
# Convert a ManagedService to JSON
j=servicemanagement_v1.ManagedService.to_json(managed_service)
print(j)
except Exception as e:
print(e)
产量:
{
"serviceName": "abusiveexperiencereport.googleapis.com",
"producerProjectId": ""
}
{
"serviceName": "acceleratedmobilepageurl.googleapis.com",
"producerProjectId": ""
}
{
"serviceName": "accessapproval.googleapis.com",
"producerProjectId": ""
}
...
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