Python sqlite 操作，SQL 语句 'where field in (1,2)' 语法错误

Question

Python sqlite 操作，SQL 语句 'where field in (1,2)' 语法错误

错误是： sqlite3.OperationalError: near ":id": syntax error

我搜索官方 Python 文档和谷歌未能找到答案：

https://docs.python.org/3/library/sqlite3.html

arguments应该如何通过？

'''first create test.db:table and field
CREATE TABLE test_tab (
    id         INTEGER PRIMARY KEY ASC,
    test_num   INT,
    test_field TEXT
);
'''

import sqlite3
con = sqlite3.connect('test.db')
con.set_trace_callback(print)  # start the debug
d = [
    (111,'aaa'),
    (111,'bbb'),
    (111,'ccc'),
    (444,'ddd')
]
sql = "insert into `test_tab` (`test_num`, `test_field`) values (?,?)"
cursor = con.executemany(sql, d)
con.commit()  # Execute successfully

#####################

# wrong code begin,why sql 'in ()' is wrong?
sql = "SELECT * from `test_tab` where `test_num`=:num AND `id` in :id"
par = {'num': 111, 'id': (1,2)}  # The number of 'id' parameters is uncertain
x = con.execute(sql, par)
print(x.fetchall())

Answer 1

在第二个查询中，您实际上需要为IN子句中的每个值使用单独的占位符。 另外，我会使用? 这里：

num = 111
ids = (1, 2)
par = (num,) + ids
sql = "select * from test_tab where test_num = ? AND id in "
in_clause = '(?' + ', ?'*(len(ids) - 1) + ')'
sql = sql + in_clause
x = con.execute(sql, par)
print(x.fetchall())

上述脚本生成的 SQL 查询为：

select * from test_tab where test_num = ? AND in (?, ?)

我们将(111, 1, 2)绑定到三个? 占位符。