更改列表的每个值的特定字符串

Question

我有一个这样的列表：

list = [
    '20211231_2300',
    '20211231_2305',
    '20211231_2310',
    '20211231_2315',
    '20211231_2320',
    '20211231_2325'
]

使用 Python，我想将列表的每个值更改为"2021/12/31_23:05"以获得此结果：

[
    '2021/12/31_23:00',
    '2021/12/31_23:05',
    '2021/12/31_23:10',
    '2021/12/31_23:15',
    '2021/12/31_23:20',
    '2021/12/31_23:25'
]

我怎样才能做到这一点？ 谢谢 ！

Answer 1

dates = [
    "20211231_2300",
    "20211231_2305",
    "20211231_2310",
    "20211231_2315",
    "20211231_2320",
    "20211231_2325",
]


def format_date(s: str) -> str:
    """assumes correct input format <yyyymmdd_hhmm>"""
    year = s[:4]
    month = s[4:6]
    day = s[6:8]
    hour = s[9:11]
    minute = s[11:]
    return f"{year}/{month}/{day}_{hour}:{minute}"


dates = [format_date(d) for d in dates]
print(dates)

Answer 2

您可以考虑使用datetime标准库中的strptime和strptime ：

from datetime import datetime

dates = [
    '20211231_2300',
    '20211231_2305',
    '20211231_2310',
    '20211231_2315',
    '20211231_2320',
    '20211231_2325'
]

fmt = [datetime.strptime(date, "%Y%m%d_%H%M").strftime("%Y/%m/%d_%H:%M") for date in dates] 

print(fmt) # prints: ['2021/12/31_23:00', '2021/12/31_23:05', '2021/12/31_23:10', '2021/12/31_23:15', '2021/12/31_23:20', '2021/12/31_23:25']