我正在尝试从字典列表中获取两个键

Question

我试图在找到密钥时打印出一条消息，以及另一个密钥的相应值。 这是我到目前为止所拥有的

l = [{'a': "dog", 'b': "black"}, {'a': "cat", 'b': "yellow"}, {'a': "bird", 'b': "blue"}] 

def search(name, value): 
    for k in list: 
        if k['brand'] == name: 
            print("The dog was found with color" + str(k['age'] == value)) 
search('dog','')

我正在尝试将 output 做到这一点

The dog was found and the color is black. 

Answer 1

l = [{'a': "dog", 'b': "black"}, {'a': "cat", 'b': "yellow"}, {'a': "bird", 'b': "blue"}]

def search_dict(l, name, key='b'):
    for dic in l:
        if name in dic.values():
            print(f"{name} was found with color {dic[key]}")

search_dict(l, 'dog')
>>> dog was found with color black

那么这里会发生什么：

1. 首先创建一个带有字典的列表（ l ）
2. function 获取包含字典的列表，在每个字典的值中查找的名称和字典颜色的键，默认key='b' 。 如果name在字典的值之一中，则它会根据key='b'打印以给定颜色找到的那个。
3. function 返回None ，它只打印找到的内容。

为什么要输入键：

l = [{'animal': 'dog', 'color':'brown'}, {'animal': 'dog', 'color':'red'},{'animal': 'cat', 'color':'brown'}]

search_dict(l, name='dog', key='color')
>>> dog was found with color brown
>>> dog was found with color red

Answer 2

如果您想检查是否存在同时包含“动物”和“颜色”的条目，我认为这段代码应该可以工作：

l = [{'a': "dog", 'b': "black"}, {'a': "cat", 'b': "yellow"}, {'a': "bird", 'b': "blue"}] 

def search(animal, color): 
    for k in l: 
        if k['a'] == animal and k['b'] == color: 
            print("The {a} was found with color {b}".format(**k)) 

search('dog', 'black')

给你：

The dog was found with color black

您只需要循环浏览列表并检查“a”和“b”的条目是否符合要求。

就我个人而言，我会使用不同的名称，而不仅仅是“a”和“b”，例如：

l = [{'animal': "dog", 'color': "black"}, {'animal': "cat", 'color': "yellow"}, {'animal': "bird", 'color': "blue"}] 

但这取决于您的要求...