![](/img/trans.png)
[英]Split a list by comma and how to exclude comma and quotations from quotes in split
[英]Split string with comma(,) and exclude list in python
我有一个字符串
'[abc, def, ijk],somedata1,somedata2,somedata3,somedata4'
我想将其拆分如下:
[['abc', 'def', 'ijk'], 'somedata1', 'somedata2', 'somedata3', 'somedata4']
但是当我使用.split(',')
时,列表也会分裂
'[abc, def, ijk],somedata1,somedata2,somedata3,somedata4'.split(',')
Output:
['[abc', ' def', ' ijk]', 'somedata1', 'somedata2', 'somedata3', 'somedata4']
Python 中有没有办法拆分,
但排除列表?
一个简单的技巧是在现有字符串周围加上引号,以便能够使用ast.literal_eval
:
import ast
import re
s = '[abc, def, ijk],somedata1,somedata2,somedata3,somedata4'
data = list(ast.literal_eval(re.subn(r'(\w+)', r"'\1'", s)[0]))
它按预期给出:
[['abc', 'def', 'ijk'], 'somedata1', 'somedata2', 'somedata3', 'somedata4']
但请注意:任何包含引号的更复杂的字符串都会立即破坏此代码......
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.