Discord.py - 给具有更多角色的用户的消息

Question

我希望我的机器人向具有两个或多个特定角色的用户写一条消息，而不仅仅是其中的一部分。

代码在这里（没有令牌）：

import discord 
import asyncio
client = discord.Client()
@client.event
async def on_message(message):
    member = message.author

    role = discord.utils.get(message.guild.roles, name="2A") and member.roles=="1B", "1C", "1D", "1E", "1F", "2B", "2C", "2D", "2E", "2F", "3A", "3B", "3C", "3D", "3E", "3F", "4A", "4B", "4C", "4D", "4E", "4F", "5A", "5B", "5C", "5D", "6A", "6B", "6C", "6D", "7A", "7B", "7C", "7D", "8A", "8B", "8C", "8D"
   if role in message.author.roles and message.content == "test":
     await message.channel.send("response")
   else:
     return

   role = discord.utils.get(message.guild.roles, name="3A") and member.roles=="1B", "1C", "1D", "1E", "1F", "2B", "2C", "2D", "2E", "2F", "3B", "3C", "3D", "3E", "3F", "4A", "4B", "4C", "4D", "4E", "4F", "5A", "5B", "5C", "5D", "6A", "6B", "6C", "6D", "7A", "7B", "7C", "7D", "8A", "8B", "8C", "8D"
   if role in message.author.roles and message.content == "test":
       await message.channel.send("response")
   else:
        return

但它没有任何反应。 甚至可以编写这样的程序吗？

Answer 1

因此，您可以制定一个更简单的解决方案，而不仅仅是通过保存名称来获取每个角色。 我宁愿用 ID 来做这件事，因为它们总是一样的

然后您可以删除member变量，因为它非常无用（您只是缩短了一个短名称）

然后检查用户必须查看的所有角色，看看它们中的任何一个是否在名称列表中（并且内容是“测试”）。

编辑：您必须仔细检查角色，因为您想知道角色中是否有两个role_names角色，您也可以将if message.content...移到顶部以保存每次遍历所有角色消息已发送

如果某个角色在名单中，你必须break for loop并继续做你之后做的事情（如果之后没有任何事情，你也可以删除else: return ）

最后看起来像这样：

import discord 
import asyncio

role_names = ["1B", "1C", "1D", "1E", "1F", "2A", "2B", "2C", "2D", "2E", "2F", "3A", "3B", "3C", "3D", "3E", "3F", "4A", "4B", "4C", "4D", "4E", "4F", "5A", "5B", "5C", "5D", "6A", "6B", "6C", "6D", "7A", "7B", "7C", "7D", "8A", "8B", "8C", "8D"]

client = discord.Client()


@client.event
async def on_message(message):
    if message.content == "test":
        role1 = None
        for role in message.author.roles:
            if role.name in role_names:
                role1 = role
            if role1 is not None and role2.name in role_names and role2.name != role1.name:
            # Check if role1 is found and role2 has another role name and is a right role
                await message.channel.send("response")
                break