打印字符串数组 - Shell 脚本

Question

亲爱的，

简单的问题，我有一个具有以下值的 shell 变量，

myarr=["Life","is","good","when","you","learning"]

它是一个字符串数组。 这是我想要打印它的方式，另外，我需要处理一个循环，因为这些元素中的每一个都将传递给 function 来处理字符串

预计 Output

Life \
is \
good \
when \
you \
learning

Answer 1

您可以创建一个 for 循环来打印数组的所有元素。

# declare your array variable
declare -a myarr=("Life","is","good","when","you","learning")

# get length of an array
length=${#myarr[@]}

for (( j=0; j<${length}; j++ ));
do
  printf "${myarr[$j]}\n"
done

Answer 2

数组文字在 shell 中声明如下：

myarr=(Life is good when you learning)

如果你有这样一个数组，你可以像这样将它传递给printf （注意扩展周围的"double quotes" ）：

printf "%s\n" "${myarr[@]}"
Life
is
good
when
you
learning

如果声明数组时单个元素中有空格，则使用"double quotes" ：

myarr=("Life is good" when you learning)
printf "%s\n" "${myarr[@]}"
Life is good
when
you
learning

您也可以只创建一个字符串值，然后不使用将拆分字符串的引号：

mys="Life is good when you learning"
printf "%s\n" $mys
Life
is
good
when
you
learning

请注意，这也会扩展 glob：

mys="Life is good when * you learning"
printf "%s\n" $mys
Life
is
good
when
...
a bunch of files from the glob in the cwd
...
file
you
learning