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[英]Removing matching observations where their adjacent column does not equal to 100
[英]Loop to clean up table where observations are stored as column
我有一个表,按以下方式在x
列中存储观察值,在y
列中存储变量名称。
我正在尝试编写一个R
循环来创建一个矩阵,其中每个观察值是一行,每个变量是一列。
问题是并非所有观察结果都包含所有变量。
原始数据:
X | 是 |
---|---|
苹果 | 水果 |
奥地利 | 起源 |
夏天 | 季节 |
橙子 | 水果 |
西班牙 | 起源 |
梨 | 水果 |
番茄 | 水果 |
意大利 | 起源 |
夏天 | 季节 |
所需的 output:
水果 | 起源 | 季节 |
---|---|---|
苹果 | 奥地利 | 夏天 |
橙子 | 西班牙 | |
梨 | ||
番茄 | 意大利 | 夏天 |
到目前为止我的想法(伪R
代码):
df_old <- data.frame( x = c( "Apple", "Austria", "Summer", "Orange", "Spain", "Pear", "Tomato", "Italy", "Summer" ),
y = c( "Fruit", "Origin", "Season", "Fruit", "Origin", "Fruit", "Fruit", "Origin", "Season" ) )
df_new <- data.frame( matrix( ncol = 3, nrow = 0 ) )
colnames( df_new ) <- c( "Fruit", "Origin", "Season")
for ( i in seq_along( df_old ) ) {
if ( y == "Fruit" ) {
# add new row
df_new$Fruit <- df_old$x
} else if ( y == "Origin" ) {
df_new$Origin <- df_old$x
} else ( y == "Season" ) {
df_new$Season <- df_old$x
}
}
谢谢你的帮忙。
这是一个基于您使用 for 循环给出的想法的解决方案。
df_old <- data.frame( x = c( "Apple", "Austria", "Summer", "Orange", "Spain", "Pear", "Tomato", "Italy", "Summer" ),
y = c( "Fruit", "Origin", "Season", "Fruit", "Origin", "Fruit", "Fruit", "Origin", "Season" ) ,stringsAsFactors=F)
df_new <- as.data.frame(matrix(NA, nrow=sum(df_old$y == "Fruit"), ncol=length(unique(df_old$y))))
names(df_new) <- c("Fruit", "Origin", "Season")
j <- 0
for (i in 1:(nrow(df_old))){
print(df_old$y[i])
if (df_old$y[i] == "Fruit") { j <- j + 1 ; df_new$Fruit[j] <- df_old$x[i]
print("new colum")
if ((df_old$y[i+1] == "Origin")){ df_new$Origin[j] <- df_old$x[i+1] }
print("add origin")
if ((df_old$y[i+1] == "Season") | (df_old$y[i+2] == "Season")){
df_new$Season[j] <- df_old$x[c(i+1,i+2)][df_old$y[c(i+1,i+2)] == "Season"]
print("add Season")
}
}
}
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