我可以通过在“__main__”中使用 try 和 catch 来捕获所有异常吗

Question

如果我在“ main ”中使用 try except 块，是否也可以捕获所有异常？ 我试着捕捉异常，但我不能。 我附上了异常图像和代码

enter code here

if __name__ == '__main__':
  try:
     app = QtWidgets.QApplication(sys.argv)
     window = MainWindow()
     debug_file = "errors.txt"
     window.setWindowFlags(QtCore.Qt.WindowType.CustomizeWindowHint)
     window.show()
     ret = app.exec_()
     [enter image description here][1]sys.exit()

except KeyboardInterrupt:
    print("Theres an exception")
    traceback_str = "".join(traceback.format_exc())
    with open("errors.txt", "a") as log:
        log.write(datetime.now().isoformat() + "\n")
        log.write(traceback_str + "\n")
        print(traceback_str)
except  AttributeError:
    print("Theres an exception")
    traceback_str ="".join(traceback.format_exc())
    with open("errors.txt","a") as log:
        log.write(datetime.now().isoformat()+"\n")
        log.write(traceback_str +"\n")
        print(traceback_str)

Answer 1

如此处所述，您可以创建异常处理程序和猴子补丁sys.excepthook ：

import sys
import logging

logger = logging.getLogger(__name__)

def handle_unhandled_exception(e_type, e_value, e_traceback):
    logger.critical("Unhandled exception", exc_info=(e_type, e_value, e_traceback))
    do_other_stuff_at_your_convenience()

sys.excepthook = handle_unhandled_exception