为什么我的输入语句不接受程序中的值？

Question

我正在制作一个生成随机数的程序，并要求您猜测 1-100 范围之外的数字。 输入数字后，它会根据该数字生成响应。 在这种情况下，如果输入为0 ，则为Too high 、 Too low 、 Correct或Quit too soon ，程序结束（简化，但基本相同）。

它根据您必须输入 function 的次数来计算尝试次数，并使用 while 循环不断询问数字，直到您输入正确为止。 （顺便说一句，是的，我意识到这部分是我另一个问题的副本。这是同一程序中的不同问题，所以我以同样的方式开始。）

无论如何，我对程序的最后一部分没有采取任何价值有疑问。 它应该接受keep_playing的输入，如果它等于'y'则继续播放。 问题是它实际上并没有使变量等于任何东西（至少我不这么认为。）所以，无论我输入什么值，它每次都会打印相同的响应。 这是代码的一小部分不起作用，尽管我觉得代码的 rest 有问题：

def keep_playing(attempts,keep_playing):
    keep_playing = 'y'
    if keep_playing == 'y':
        guess(attempts)
        keep_playing = str(input("Another game (y to continue)? "))
    else:
        print()
        print("Thanks for playing")
    return keep_playing

预期的 output 是：

Enter a number between 1 and 100, or 0 to quit: 4
Too low, try again       It's 66 for testing purposes
Enter a number between 1 and 100, or 0 to quit: 67
Too high, try again      It's 66 for testing purposes
Enter a number between 1 and 100, or 0 to quit: 66

Congratulations! You guessed the right number!
There were 2 attempts

Another game (y to continue)? y

Enter a number between 1 and 100, or 0 to quit: 0

You quit too early
The number was  79
Another game (y to continue)? n

Thanks for playing!

但实际的 output 是：

Enter a number between 1 and 100, or 0 to quit: 4
Too low, try again       It's 66 for testing purposes
Enter a number between 1 and 100, or 0 to quit: 67
Too high, try again      It's 66 for testing purposes
Enter a number between 1 and 100, or 0 to quit: 66

Congratulations! You guessed the right number!
There were 2 attempts

Another game (y to continue)? y

Enter a number between 1 and 100, or 0 to quit: 0

You quit too early
The number was  79
Another game (y to continue)? n
Another game (y to continue)? y
>>>

请注意，无论我做什么，它都会继续运行。 较高和较低的第一部分工作正常，但底部似乎坏了，我不知道如何修复它。 如果有人有任何解决方案，将不胜感激。

另外，如果有人想看到整个事情，如果有问题的话，这里是：

import random

def main():
    global attempts
    attempts = 0
    guess(attempts)
    keep_playing(attempts,keep_playing)
    
def guess(attempts):
    number = random.randint(1,100)
    print('')
    guess = int(input("Enter a number between 1 and 100, or 0 to quit: "))
    while guess != 0: 
        if guess != number:
            if guess < number:
                print("Too low, try again       It's",number, "for testing purposes") #printing the number makes it easier to fix :/
                attempts += 1
                guess = int(input("Enter a number between 1 and 100, or 0 to quit: "))
            elif guess > number:
                print("Too high, try again      It's",number, "for testing purposes")
                attempts += 1
                guess = int(input("Enter a number between 1 and 100, or 0 to quit: "))
        else:
            print()
            print("Congratulations! You guessed the right number!")
            print("There were", attempts,"attempts")
            print()
            keep_playing = str(input("Another game (y to continue)? "))
            return keep_playing
            
    else:
        print()
        print("You quit too early")
        print("The number was ",number)
        keep_playing = str(input("Another game (y to continue)? "))
        return keep_playing
        
    
    

def keep_playing(attempts,keep_playing):
    keep_playing = 'y'
    if keep_playing == 'y':
        guess(attempts)
        keep_playing = str(input("Another game (y to continue)? "))
    else:
        print()
        print("Thanks for playing")
    return keep_playing
main()
            

Answer 1

我注意到这里有几件事

1. 您的 function 的命名存在一些问题，python 认为keep_playing是 str 变量keep_playing而不是 function。在我下面的代码中，我将 function keep_playing重命名为keep_playing_game 。
2. 您需要在调用 function keep_playing_game时传入参数，以便 function 知道用户输入和尝试的内容。
3. 为什么要在 function def keep_playing_game(attempts,keep_playing)的第一行中设置keep_playing = 'y' ？ 如果删除此行，您的程序应根据用户输入的值而不是 function 分配给keep_playing的值按预期运行。

我建议尝试这样的事情

import random

def main():
    global attempts
    attempts = 0
    guess(attempts)
    # keep_playing(attempts,keep_playing) -> this line should be removed
    
def guess(attempts):
    number = random.randint(1,100)
    print('')
    guess = int(input("Enter a number between 1 and 100, or 0 to quit: "))
    while guess != 0: 
        if guess != number:
            if guess < number:
                print("Too low, try again       It's",number, "for testing purposes") #printing the number makes it easier to fix :/
                attempts += 1
                guess = int(input("Enter a number between 1 and 100, or 0 to quit: "))
            elif guess > number:
                print("Too high, try again      It's",number, "for testing purposes")
                attempts += 1
                guess = int(input("Enter a number between 1 and 100, or 0 to quit: "))
        else:
            print()
            print("Congratulations! You guessed the right number!")
            print("There were", attempts,"attempts")
            print()
            keep_playing = str(input("Another game (y to continue)? "))
            return keep_playing_game(keep_playing, attempts)
            
    else:
        print()
        print("You quit too early")
        print("The number was ",number)
        keep_playing = str(input("Another game (y to continue)? "))
        return keep_playing_game(keep_playing, attempts)
        
    
    

def keep_playing_game(keep_playing, attempts):
    if keep_playing == 'y':
        guess(attempts)
    else:
        print()
        print("Thanks for playing")
        return
    return None
main()