如何在python中使用select下面的元素selenium

Question

我正在尝试 select 的元素是下面的那个

<div id="mOnlineEligiblity" class="col span_1_of_3" style="">
  <a href="onlineElig.html" style="text-decoration: none !important;color: #275883;"><img src="../../images/mobileHome/Newicon/OnlineEligibility.png" height="65px" width="65px" class="morph">
  <br> Online Eligibility </a>
</div>

我尝试了以下 select 它，但它说找不到元素

driver.find_element_by_id("mOnlineEligiblity")

NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":"[id="mOnlineEligiblity"]"}

我希望能够 select 然后点击它

编辑： -

它存在于iframe中，如 Swaroop 所述，附上图像以供参考

Answer 1

不得不像 Swaroop 提到的那样切换到iframe 。

# Find the iframe
iframe = driver.find_element_by_xpath("//iframe[@name='NAME_OF_THE_FRAME']")

# Switch to the iframe
driver.switch_to.frame(iframe)

# Now find the element
driver.find_element_by_id("mOnlineEligiblity").click()

Answer 2

只要它确实在您正在加载的页面上（不在 iframe 中），那么找到它并单击它就不会有任何问题。

import platform
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.firefox.options import Options

options = webdriver.ChromeOptions()
if platform == "linux" or platform == "linux2":
    driver = webdriver.Chrome(executable_path='chromedriver_linux', chrome_options=options)
elif platform == "darwin":
    driver = webdriver.Chrome(executable_path='chromedriver_mac', chrome_options=options)
else:
    driver = webdriver.Firefox()

    driver.maximize_window()

    timeout = 10

    driver.get("file:///G:/Downloads/random.html")

    xpath = '//*[@id="mOnlineEligiblity"]/a'
    WebDriverWait(driver, timeout).until(EC.element_to_be_clickable((By.XPATH, xpath)))

    link_to_click = driver.find_element(By.XPATH, XPath)

    link_to_click.click()

    driver.quit()

我仍然建议通过xpath = '//*[@id="mOnlineEligiblity"]/a'定位您实际想要点击的元素，而不仅仅是xpath = '//*[@id="mOnlineEligiblity"]'但如果它是一次性脚本，那么这更像是一种最佳实践，而不是你需要担心的任何事情。