[英]Open Pie Chart/Donut Chart in R using Plotly with count and percentage
[英]Pie-Donut Chart in R
我想创建一个如下图所示的 Pie-Donut 图表:
为此,我正在使用下一个代码:
PieDonut(df1, aes(Species, Costs, count=Entries),
ratioByGroup = F, explode = 1, r0 = 0.5, r1 = 0.7)
正如您所看到的,两组的比率是不一样的:第一个甜甜圈应该根据变量“Costs”,第二个应该根据变量“Entries”
这是我正在使用的数据:
structure(list(Species = c("Cercopagis pengoi", "Dreissena polymorpha"
), Costs = c(0.27, 33.27), Entries = c(7L, 5L), fraction = c(0.00805008944543828,
0.991949910554562), ymax = c(0.00805008944543828, 1), ymin = c(0,
0.00805008944543828)), row.names = c(NA, -2L), class = c("tbl_df",
"tbl", "data.frame"))
我真的很感激一些帮助,提前致谢。
在这里,我得到了一个plotly
选项。 您可以使用两个add_pie
使用 plotly 创建两个饼图,一个用于孔,一个用于外圆。 您可以使用以下代码:
library(plotly)
library(dplyr)
plot_ly(df1) %>%
add_pie(labels = ~`Species`, values = ~`Costs`,
type = 'pie', hole = 0.7, sort = F,
marker = list(line = list(width = 2))) %>%
add_pie(df1, labels = ~`Species`, values = ~`Entries`,
domain = list(
x = c(0.15, 0.85),
y = c(0.15, 0.85)),
sort = F) %>%
layout(title = "Chart",
legend = list(title = list(text = "Species")))
Output:
df1 <- structure(list(Species = c("Cercopagis pengoi", "Dreissena polymorpha" ), Costs = c(0.27, 33.27), Entries = c(7L, 5L), fraction = c(0.00805008944543828, 0.991949910554562), ymax = c(0.00805008944543828, 1), ymin = c(0, 0.00805008944543828)), row.names = c(NA, -2L), class = c("tbl_df", "tbl", "data.frame"))
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