[英]How to combine a list of cuminc curves? E.g. using ggcompetingrisks?
[英]How to convert char (e.g., "[1, 2, 3]" ) to a list (e.g., [1, 2, 3])
有没有一种很好的方法可以将 dataframe 中的一列字符转换为 R Studio 中的列表?
例如
转换类型 chr
"[1, 2, 3]"
"[11, 24, 3]"
"[1, 21, 3]"
"[14, 2, 31]"
列出
[1, 2, 3]
[11, 24, 3]
[1, 21, 3]
[14, 2, 31]
这些不是 R 中的列表; 它们看起来像 python(语言)和 json(结构)中的列表。 我们可以利用后者:
vec <- c("[1, 2, 3]", "[11, 24, 3]", "[1, 21, 3]", "[14, 2, 31]")
jsonlite::stream_in(textConnection(paste(vec, collapse = "\n")),
simplifyDataFrame = FALSE, simplifyMatrix = FALSE)
# Imported 4 records. Simplifying...
# [[1]]
# [1] 1 2 3
# [[2]]
# [1] 11 24 3
# [[3]]
# [1] 1 21 3
# [[4]]
# [1] 14 2 31
gsub
+ str2lang
+ eval
怎么样?
> s <- c("[1, 2, 3]", "[11, 24, 3]", "[1, 21, 3]", "[14, 2, 31]")
> lapply(gsub("\\[(.*)\\]", "c(\\1)", s), function(x) eval(str2lang(x)))
[[1]]
[1] 1 2 3
[[2]]
[1] 11 24 3
[[3]]
[1] 1 21 3
[[4]]
[1] 14 2 31
另一种选择是使用reticulate
py_eval
中的 py_eval
> library(reticulate)
> lapply(s, py_eval)
[[1]]
[1] 1 2 3
[[2]]
[1] 11 24 3
[[3]]
[1] 1 21 3
[[4]]
[1] 14 2 31
这是一种使用strsplit
的方法。
strsplit(x, '\\D+') |> lapply(`[`, -1)
# [[1]]
# [1] "1" "2" "3"
#
# [[2]]
# [1] "11" "24" "3"
#
# [[3]]
# [1] "1" "21" "3"
#
# [[4]]
# [1] "14" "2" "31"
数据:
x <- c("[1, 2, 3]", "[11, 24, 3]", "[1, 21, 3]", "[14, 2, 31]")
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