[英]Python regex replace list of pattern
我有一个模式列表:
patterns = ["how", "do you do", "are you doing", "goes it"]
字符串中出现的任何列表项都应替换为"how are you" 。
例如:
字符串“你好吗?” 应该换成“你好吗?”
我用什么:
s = input()
for pattern in patterns:
s = re.sub(rf"(\b{pattern}\b)", "how are you", s)
问题是我收到"how are you how are you" 。
最简单的解决方案是将模式列表更改为:
patterns = ["how do you do", "how are you doing", "how goes it"]
但我需要将“如何”保留在列表中并将其与其他项目分开。
问题与re.sub
内部和外部的s
有关,这会覆盖input()
使用另一个 varialbe,例如m
s = input()
for pattern in patterns:
m = re.sub(rf"(\b{pattern}\b)", "how are you", s)
请您尝试以下操作:
import re
patterns = ["how", "do you do", "are you doing", "goes it"]
first = patterns.pop(0) # pop the 1st element
pattern = rf"\b{first}\s+(?:" + "|".join(patterns) + r")\b"
# pattern equals to r"\bhow\s+(?:do you do|are you doing|goes it)\b"
s = input()
s = re.sub(pattern, "how are you", s)
print(s)
如果您更喜欢使用循环,可以使用以下替代方法:
import re
patterns = ["how", "do you do", "are you doing", "goes it"]
first = patterns.pop(0) # pop the 1st element
s = input()
for pattern in patterns:
s = re.sub(rf"\b{first}\s+{pattern}\b", "how are you", s)
print(s)
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