Python，每个用户输入的新唯一 object

Question

初级程序员在这里。 我创建了一个 class 使学生成为 object，我需要一种方法来为用户创建的每个 object 不覆盖以前的对象并使它们完全相同。 这可能是一个糟糕的解释，所以我将只发布代码和 output。

class Student:
    """This class holds student records """
    student_id = 000
    def __init__(self,firstname='blank',lastname='blank',age=0,sex='NA',major='undeclared',graduation=0):
        self.firstname = firstname
        self.lastname = lastname
        self.age = age
        self.sex = sex
        self.major = major
        self.graduation= graduation
        Student.student_id +=1
        self.student_id = Student.student_id


students=[]
while True:
    new_student=Student(input('Enter student first name: '),input('Enter student last name: '),input('Enter student age: '),input("Enter student sex: "),input("Enter student's major: "),input("Enter student's expected graduation date: "))
    students.append(new_student)
    add_another=input("Would you like to add another student? Enter 'Y' for yes or any other key to quit and print your entries: ")
    if add_another == 'Y':
        continue
    else:
        for i in students:
            print(new_student.firstname)
            print(new_student.student_id)
        break

我的 output 目前看起来像这样：

Enter student first name: Thomas
Enter student last name: Hutton
Enter student age: poop
Enter student sex: p
Enter student's major: p
Enter student's expected graduation date: p
Would you like to add another student? Enter 'Y' for yes or any other key to quit and print your entries: Y
Enter student first name: Timmy
Enter student last name: p
Enter student age: p
Enter student sex: p
Enter student's major: p
Enter student's expected graduation date: p
Would you like to add another student? Enter 'Y' for yes or any other key to quit and print your entries: n
Timmy
2
Timmy
2

如您所见，现在填充学生列表的唯一 object 现在对于两个条目都是相同的 object，我需要它们是用户提供的条目。 谢谢你的帮助。

Answer 1

您正在创建的 object 并没有覆盖之前的，问题出在您的打印循环上：

for i in students:
    print(new_student.firstname)
    print(new_student.student_id)
break

它不会打印列表中的所有学生，它总是打印最后添加的学生（这是new_student变量）。 要解决这个问题，你可以这样做：

for student in students:
    print(student.firstname)
    print(student.student_id)
break

Answer 2

当您遍历学生时，您没有引用正确的变量。 new_student应该是i

for i in students:
    print(i.student_id)
    print(i.firstname)

但我建议将 i 变量更改为学生，所以它看起来像

for student in students:
    print(student.firstname)

i通常用于表示列表中的 integer 索引。

Answer 3

您不需要临时的new_student 。

只需将 append 直接添加到学生列表中，而不使用（不是这样）临时变量。 与提示另一个相同。

class Spam:
    """Spiced meat"""
    def __init__(self, firstname=''):
        self.firstname = firstname

    def __repr__(self):
        return self.firstname
  
lunch = []
while True:
    lunch.append(Spam(input('Enter name: ')))
    if input('Another one? ') in ('y', 'Y'):
        continue
    else:
        break

for meat in lunch:
    print(meat)