如何在条件满足时退出While循环

Question

如果条件满足并打印我预期的 output，我有一个无限循环需要退出脚本

代码：

import random

stud=[0,0]
studnme = ['a','b']

while (stud[0] !=50 or stud[1] !=50):
    if flag = 0:
        lucky_draw = random.randint(1,6)
        stud_marks = stud[0] + lucky_draw
        stud[0]    = stud[0] + lucky_draw  
        flag=1 
    else:
        lucky_draw = random.randint(1,6)
        stud_marks = stud[1] + lucky_draw
        stud[0]    = stud[1] + lucky_draw  
        flag=0         

Output：

Student 'a' You have reached : 50
Student 'b' You have reached : 34

需要打印谁是最高分

Answer 1

您要测试以退出循环的值会按随机值递增，因此不能保证它们正好达到 50。 当这些值小于 50 时使循环运行。

while (stud[0] < 50 and stud[1] < 50):

Answer 2

import random

stud=[0,0]
studnme = ['a','b']
flag=0
while (stud[0] <=50 or stud[1] <=50):
    if flag == 0:
        lucky_draw = random.randint(1,6)
        stud_marks = stud[0] + lucky_draw
        stud[0]    = stud[0] + lucky_draw  
        flag=1 
    else:
        lucky_draw = random.randint(1,6)
        stud_marks = stud[1] + lucky_draw
        stud[1]    = stud[1] + lucky_draw  
        flag=0      
print(f'Student a you have reached :{stud[0]}')
print(f'Student b you have reached :{stud[1]}')

首先，您没有定义标志，因此将其设置为 0 或 1，并且您保留的条件也应该稍微改变一下，即任何学生的分数大于 50 程序应该终止。 请检查上面的代码。