如何在 AND 条件下使用 root.findall

Question

XML 是这样的：

<Section SectionLevel="1" SectionID="Food">
    <Section SectionLevel="2" SectionID="Fruit">
        <Content>Apple</Content>
</Section>
        
<Section SectionLevel="1" SectionID="Food">
    <Section SectionLevel="2" SectionID="Meat">
        <Content>Beef</Content>
</Section>

当级别 1 中的 SectionID = Food 和级别 2 中的 SectionID = Fruit 时，我想打印内容。 我找不到在 AND 条件下使用 XPath 的教程。

def main():
    tree = ET.parse('data.xml')
    root = tree.getroot()
    for section in root.findall("./Section/[SectionID='Food']"):

    and

    for section in root.findall("./Section/Section/[SectionID='Fruit']"):

    print(content)

Answer 1

在 xpath 中有and ，但我认为在这种情况下您不需要它。 我想你只需要把你的两个 xpath 放在一起......

.//Section[@SectionID='Food']/Section[@SectionID='Fruit']/Content

完整的例子...

import xml.etree.ElementTree as ET
from io import StringIO  # using StringIO to simulate reading a file instead of a string

xml = """<doc>
<Section SectionLevel="1" SectionID="Food">
    <Section SectionLevel="2" SectionID="Fruit">
        <Content>Apple</Content>
    </Section>
</Section>
        
<Section SectionLevel="1" SectionID="Food">
    <Section SectionLevel="2" SectionID="Meat">
        <Content>Beef</Content>
    </Section>
</Section>
</doc>"""

doc = StringIO(xml)
tree = ET.parse(doc)

for content_elem in tree.findall(".//Section[@SectionID='Food']/Section[@SectionID='Fruit']/Content"):
    print(content_elem.text)

印output...

Apple