xcode 13 - 尝试使用公共 function 每 30 秒触发一次本地通知

Question

我试图每 30 秒触发一次本地通知，但出现错误“Type '()' cannot conform to 'View'” 我刚刚在 Xcode 13 上打开了一个新项目，它说你好世界并想触发本地在“hello world”ContentView() function 之后使用以下 A() 函数进行通知

我究竟做错了什么？ 有更好的方法吗？

谢谢++++++++++++++++++

import SwiftUI
import UserNotifications

@main
struct ozApp: App {
    var body: some Scene {
        WindowGroup {    /// error /// Type '()' cannot conform to 'View'            
            ContentView()
            A()
        }
    }
}

public func A(){
    // Swift
    let content = UNMutableNotificationContent()
    content.title = "Title"
    content.body = "Body"
    content.sound = UNNotificationSound.default
                   
    let trigger = UNTimeIntervalNotificationTrigger(timeInterval: 30, repeats: true)

    let request = UNNotificationRequest(identifier: UUID().uuidString, content: content, trigger: trigger)
    print("INSIDE NOTIFICATION")
    
   // let request = UNNotificationRequest(identifier: CommonViewController.Identifier, content: content, trigger: trigger)
    //print("INSIDE NOTIFICATION")
                    
    UNUserNotificationCenter.current().add(request, withCompletionHandler: {(error) in
        if let error = error {
            print("SOMETHING WENT WRONG")
        }
    })
    

}

Answer 1

尝试这个：

@main
struct ozApp: App {
    var body: some Scene {
        WindowGroup {
            ContentView()
              .onAppear { A() }
        }
    }
}

如果重复，时间间隔必须至少为 60。