dplyr 总结组不展平数据

Question

我有一个数据集：

df <- structure(list(ID = c(101188, 101192, 101193, 101196, 101198, 
101202, 101203, 101206, 101211, 101212, 101216, 101219, 101220, 
101222, 101223, 101224, 101226, 101227, 101228, 101229), LA = c("Barking and Dagenham", 
"Barking and Dagenham", "Barking and Dagenham", "Barking and Dagenham", 
"Barking and Dagenham", "Barking and Dagenham", "Barking and Dagenham", 
"Barking and Dagenham", "Barking and Dagenham", "Barking and Dagenham", 
"Barking and Dagenham", "Barking and Dagenham", "Barking and Dagenham", 
"Barking and Dagenham", "Barking and Dagenham", "Barking and Dagenham", 
"Barking and Dagenham", "Barking and Dagenham", "Barking and Dagenham", 
"Barking and Dagenham"), EstablishmentGroup = c("Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools", "Local authority maintained schools", 
"Local authority maintained schools")), row.names = c(NA, -20L
), class = c("tbl_df", "tbl", "data.frame"))

如果我运行以下代码，我希望最终的总结能够展平数据并告诉我

df %>%
  group_by(LA) %>%
  mutate(All_schools = n()) %>%
  ungroup() %>%
  group_by(LA, EstablishmentGroup, All_schools) %>%
  summarise(total = n(),
            per = total/All_schools)

Barking 和 Dagenham 地方当局维持学校 20 20 1

但它给了我 20 行。 我可以使用不同的，但不确定我做错了什么。

Answer 1

您可以先汇总计数，然后变异以计算百分比。

df %>%
  group_by(LA) %>%
  mutate(All_schools = n()) %>%
  ungroup() %>% 
  group_by(LA, EstablishmentGroup, All_schools) %>% 
  summarise(total = n()) %>% 
  mutate(per = total/All_schools)

输出：

# A tibble: 1 x 5
# Groups:   LA, EstablishmentGroup [1]
  LA                   EstablishmentGroup                 All_schools total   per
  <chr>                <chr>                                    <int> <int> <dbl>
1 Barking and Dagenham Local authority maintained schools          20    20     1