从字典中替换字符串中的多个单词

Question

有一个缩写字典，键是缩写，值是它的定义（“TTYL”、“稍后再谈”）。 当用户输入超过 1 个 abbreviation 的内容时，我想要一个程序用定义替换缩写作为原始输入的补充。 我让程序正常工作，但只有 1 个缩写。 我希望它能够处理字符串中超过 1 个的缩写。 我相信该解决方案与嵌套的 for 循环有关，但是我不确定并且需要一些帮助。

蟒蛇代码：

abbreviationsDictionary = {
    "ADBA":"As Directed By Arborist",
    "CRTS":"Crown Reduced To Shape",
    "NWIC":"Noob Will Improve Company"
    }

note = input("Enter note: ")
listOfWordsInNote = note.split()

updatedNote = ""
for key in abbreviationsDictionary:
    for word in listOfWordsInNote:
        if (key==word):
            updatedNote = note.replace(key,abbreviationsDictionary[key])

print(updatedNote)

电流输出（仅适用于 1 个缩写）：

Enter note: mike is going to do whatever ADBA because he knows NWIC
mike is going to do whatever ADBA because he knows Noob Will Improve Company

期望的输出

Enter note: mike is going to do whatever ADBA because he knows NWIC
mike is going to do whatever As Directed By Arborist because he knows Noob Will Improve Company

Answer 1

你的错误是你使用

updatedNote = note.replace(key,abbreviationsDictionary[key])

因此，每次找到新密钥时，您都会使用 note 重新启动（未更改）

只需替换为：

            note = note.replace(key,abbreviationsDictionary[key]) 

并打印（注）：
迈克将按照 Arborist 的指示做任何事情，因为他知道 Noob 会改善公司

Answer 2

与其替换输入字符串，不如从用户输入中获取 [空格分隔] 标记，然后使用简单的生成器进行重构：

abbreviationsDictionary = {
    "ADBA": "As Directed By Arborist",
    "CRTS": "Crown Reduced To Shape",
    "NWIC": "Noob Will Improve Company"
}

note = input("Enter note: ")

print(' '.join(abbreviationsDictionary.get(loin, loin) for loin in note.split()))