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[英]What happens if I return from a function without calling pthread_mutex_unlock?
[英]What happens when a thread calls pthread_mutex_unlock on an already unlocked mutex
我知道这个问题听起来很熟悉,甚至可能是一个愚蠢的问题,但我无法找到解决方案。
所以我的问题基本上是,当parent_thread
调用pthread_mutex_lock(&mutex)
然后调用pthread_cond_wait(&condition, &mutex)
释放互斥锁,然后child_thread
调用pthread_mutex_lock(&mutex)
后跟pthread_cond_signal(&condition)
然后pthread_mutex_unlock(&mutex)
会发生什么。 所以这意味着互斥锁已解锁,现在如果parent_thread
尝试调用pthread_mutex_unlock(&mutex)
,它应该导致未定义的行为,对吧?
示例代码:
pthread_mutex_t m = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t c = PTHREAD_COND_INITIALIZER;
void thr_exit() {
pthread_mutex_lock(&m);
done = 1;
pthread_cond_signal(&c);
pthread_mutex_unlock(&m);
}
void *child(void *arg) {
printf("child\n");
thr_exit();
return NULL;
}
void thr_join() {
pthread_mutex_lock(&m);
while (done == 0)
pthread_cond_wait(&c, &m);
pthread_mutex_unlock(&m);
}
int main(int argc, char *argv[]) {
printf("parent: begin\n");
pthread_t p;
pthread_create(&p, NULL, child, NULL);
thr_join();
printf("parent: end\n"); return 0;
}
对不起,我评论的时候才看你的标题。 只是为了确保我了解您的操作顺序,已发布答案的冗长版本:
家长来电:
pthread_mutex_lock(&m); // locks the mutex
pthread_cond_wait(&c, &m); // releases the mutex
孩子打电话:
pthread_mutex_lock(&m); // locks the mutex
pthread_cond_signal(&c); // does nothing to the mutex, it's still locked
// the parent thread has been signaled, but it is still blocked
// because it can't acquire the mutex.
// At this moment in time, the child still owns the mutex, so
// pthread_cond_wait cannot acquire it, thus the parent waits...
pthread_mutex_unlock(&m); // releases the mutex
// ok, the child released the mutex and the parent thread has been signaled.
// The mutex is available. pthread_cond_wait in the parent can
// acquire it and return.
家长来电:
// now that the mutex is unlocked, the parent can return from its
// pthread_cond_wait(&c, &m) call from above, which returns with the mutex
// locked. A successful call to pthread_cond_wait(..) returns with the
// mutex locked, so this can't successfully return until it acquires the
// mutex.
pthread_mutex_unlock(&m); // releases the locked mutex, no UB
当然,这只是几个操作顺序之一。 我认为您的误解是pthread_cond_wait
在获取互斥锁之前无法成功返回。 此时,它正确调用pthread_mutex_unlock(&m);
在锁定的互斥体上。
所以这意味着互斥锁已解锁
不, pthread_cond_wait
返回并锁定互斥锁。
如果 parent_thread 尝试调用 pthread_mutex_unlock(&mutex)
在pthread_cond_wait
返回后,父级仅解锁互斥锁。
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