PYCord 如何通过视图获取消息？

Question

https://media.discordapp.net/attachments/977648291770667010/977648292206903336/unknown.png

正如您在屏幕截图中看到的，PyCord 官方网站上有关于如何在超时到期时编辑消息内容的说明。

但正如您在此屏幕截图中看到的那样： https ://media.discordapp.net/attachments/977648291770667010/977648292655677440/unknown.png

PyCharm 说没有称为“消息”的字段。

调试时出现同样的错误：

https://media.discordapp.net/attachments/977648291770667010/977651067007426670/unknown.png?width=1200&height=123

这是我的代码：

    class UIAgreement(View):

    def __init__(self, client: Stragate):
        super().__init__(timeout=10)
        self.client = client

    async def on_timeout(self):

        self.disable_all_items()

        await self.message.edit(content="You took too long! Try again.", view=self)

    @button(label="Accept", style=ButtonStyle.success, emoji="👍")
    async def accept_callback(self, event_button: Button, event_interaction: Interaction):

        cursor = self.client.database.cursor()
        cursor.execute(f"SELECT * FROM profiles WHERE id={event_interaction.user.id} LIMIT 1")

        if not cursor.fetchone():
            cursor = self.client.database.cursor()

            cursor.execute("INSERT INTO profiles (id, full_name, job, country, description, thumbnail, "
                           "gender) VALUES (%s, %s, DEFAULT, DEFAULT, DEFAULT, %s, DEFAULT)",
                           (
                               event_interaction.user.id,
                               event_interaction.user.display_name,
                               "https://media.discordapp.net/attachments/976061052548694036"
                               "/977291014047936552/default.jpg"
                           ))
            self.client.database.commit()

            await event_interaction.user.send(embed=Embed(
                title="Successfully registered!",
                description="Please use the 'start' command again."
            ))```


  [1]: https://i.stack.imgur.com/ymKyQ.png

Answer 1

我了解到“消息”字段是我需要设置超出范围的字段。 这就是他们在不和谐服务器中所说的。 我猜指南有点过时了。