如何在程序中的字典内查询列表中的项目？

Question

def Program():
Storage = {}
while True:
    print('1 - Query parts\n2 - Add part\n3 - Delete part\n4 - Exit\n')
    choice = int(input())
    if choice == 1:
        while True:
            print(
                '1 - Consult All Parts\n2 - Consult Parts by Code\n3 - Consult Parts by Manufacturer\n4 - Return')
            choice2 = int(input())
            if choice2 == 1:
                for items in Storage.keys():
                    print(f'Code: {items} \n{Storage[items]}')
            elif choice2 == 2:
                search = input('Enter search: ')
                print(Storage[search])
            elif choice2 == 3:
                search = str(input('Enter the search: '))
                print(Storage[search])
            elif choice2 == 4:
                break
    elif choose == 2:
        Storage[input('Code: ')] = {'Name': input('Enter item name: '), 'brand': input('Enter item brand: '), 'value(R$) ': input('Enter the value of the item: ')}
    elif choose == 3:
        Storage.remove[input('Choose a part to remove: ')]
    elif choose == 4:
        break

程序（）

我需要通过制造商和代码执行这部分查询，我对python比较陌生，几天来我一直在尝试几种替代方案，但到目前为止我还没有任何进展

Answer 1

一个更简单的方法是集成一个list并用每个dictionary填充它，现在在咨询时，您会浏览列表并询问代码和制造商。

代码是这样的：

def Program():
  Storage = {}
  List = []
  while True:
      print('1 - Query parts\n2 - Add part\n3 - Delete part\n4 - Exit\n')
      choice = int(input())
      if choice == 1:
          while True:
              print(
                  '1 - Consult All Parts\n2 - Consult Parts by Code\n3 - Consult Parts by Manufacturer\n4 - Return')
              choice2 = int(input())
              if choice2 == 1:
                for item in List:
                  print(item)
              elif choice2 == 2:
                  search = input('Enter search: ')
                  for item in List:
                      if item.get("Code") == search: print(item)
              elif choice2 == 3:
                  search = input('Enter the search: ')
                  for item in List:
                      if item.get("brand") == search: print(item)
              elif choice2 == 4:
                  break
      elif choice == 2:
          Storage = {'Code': input('Code: '), 'Name': input('Enter item name: '), 'brand': input('Enter item brand: '), 'value(R$) ': input('Enter the value of the item: ')}
          List.append(Storage)
      elif choice == 3:
          for item in List:
              item.remove[input('Choose a part to remove: ')]
      elif choice == 4:
          break

Program()