在JQ中按字段选择对象并打印父键

Question

我正在寻找一种方法从 JSON 列表中提取父键名称，如下所示：

{
    "london1.perfect-privacy.com": {
        "city": "London",
        "city_short": "lo",
        "country": "United Kingdom",
        "country_short": "gb",
        "lati": "51.511214",
        "longi": "-0.119824"
    },
    "london2.perfect-privacy.com": {
        "city": "London",
        "city_short": "lo",
        "country": "United Kingdom",
        "country_short": "gb",
        "lati": "51.511214",
        "longi": "-0.119824"
    },
    "rotterdam2.perfect-privacy.com": {
        "city": "Rotterdam",
        "city_short": "ro",
        "country": "Netherlands",
        "country_short": "nl",
        "lati": "51.924216",
        "longi": "4.481776" 
    }
}

在这种情况下，父键是服务器名称，并且希望通过选择特定国家来使用 JQ by 来提取这些名称。 下面的代码让我可以提取所有父键，但我无法将其缩小到仅属于特定国家/地区的那些：

jq -r 'keys' serverlocations.json

结果：

london1.perfect-privacy.com
london2.perfect-privacy.com
rotterdam2.perfect-privacy.com

所以当我尝试这样的事情时，我得到了一个很大的错误......

jq -r 'keys | select(.country == "United Kingdom")' serverlocations.json"

错误：

jq: error (at <stdin>:0): Cannot index array with string "country"

我本来期望并希望得到这些结果：

london1.perfect-privacy.com
london2.perfect-privacy.com

非常感谢您的建议和专业知识！

Answer 1

to_entries[] | select( .value.country_short == "gb" ) | .key

jqplay上的演示

Answer 2

这是一种方法：

path(.[] | select(.country == "United Kingdom"))[0]

^在线演示