Django Table2获取值绑定列

Question

我很困惑，请告诉我如何在 Table.render_foo 方法中获取另一个Term_Implementation字段的值？

Table.render_foo 方法

绑定列

BoundColumn-getitem

class EvensList(IncidentsTable, tables.Table):

    class Meta:
        model = AkpEvents
        
        sequence = ('Term_Implementation', 'Status')

    Term_Implementation = tables.DateColumn(empty_values=(),)

    Status = tables.Column(empty_values=(),)

   def render_Status(self, value, column, columns):
        if value == 'Выполнено':
            column.attrs = {'td': {'class': 'table-success'}}

        elif value == 'В работе':
            column.attrs = {'td': {'class': 'table-warning'}}

        elif columns['Term_Implementation'] <= date.today():
            column.attrs = {'td': {'class': 'table-danger'}}

        else:
            column.attrs = {'td': {'class': ''}}

        return value

Answer 1

为了解决这个问题，你只需要使用record函数的内置参数，它会返回整个对象。

def render_Status(self, value, record, column):
    if value == 'Выполнено':
        column.attrs = {'td': {'class': 'table-success text-center align-middle'}}

    elif value == 'В работе':
        column.attrs = {'td': {'class': 'table-warning text-center align-middle'}}

    elif record.Term_Implementation <= date.today():
        column.attrs = {'td': {'class': 'table-danger text-center align-middle'}}

    else:
        column.attrs = {'td': {'class': 'text-center align-middle'}}

    return value