[英]Python: local variable not recognized
我是 python 新手,我正在尝试实现一个反转链接列表的函数。
我收到错误消息:分配前引用了局部变量“new_head”
def reverseList(self, head: Optional[ListNode]) -> Optional[ListNode]:
if head == None or head.next == None:
return head
new_head = None
def recur(curr_head):
if curr_head == None:
return
next_node = curr_head.next
curr_head.next = new_head
new_head = curr_head
recur(next_node)
recur(head)
return new_head
以下实现有效,但非常难看,是否有替代方法?
def reverseList(self, head: Optional[ListNode]) -> Optional[ListNode]:
if head == None or head.next == None:
return head
new_head = None
arr = [new_head]
def recur(curr_head):
if curr_head == None:
return
temp = curr_head.next
curr_head.next = arr[0]
arr[0] = curr_head
recur(temp)
recur(head)
return arr[0]
在函数recur
的开头,您可以输入:
nonlocal new_head
这允许内部函数recur
修改在外部函数作用域中声明的变量。
(这就像您需要使用global
来允许函数修改模块范围变量的方式。)
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