Django 在保存时自动将当前用户保存在模型中

Question

我试图在保存新数据时自动保存用户。 我的意思是我想为发布新事物（提交表单）的用户保存用户 ID，而不要求该用户从下拉列表中选择他的帐户（来自 User ForeignKey 的下拉列表）

尝试 1：

模型.py

class Feedback(models.Model):
       .
       .
    author = models.ForeignKey(
        get_user_model(),
        on_delete=models.CASCADE,
        editable=False,
        )

    def save(self, *args, **kwargs):
        self.author = get_user_model().objects.get(id=2)    #############
        return super().save(*args, **kwargs)

如果我对用户 ID get(id=2)进行硬编码，它就可以工作。 如何使 id 动态化？

编辑：

尝试 2：

我也试过用视图来做：

模型.py

class Feedback(models.Model):
       .
       .
    author = models.ForeignKey(
        get_user_model(),
        on_delete=models.CASCADE,
        editable=False,
        null=True
        blank=True
        )

    # without save()

视图.py

class FeedbackForm(ModelForm):
    class Meta:
        model = Feedback
        fields = "__all__"


class FeedbackListView(generics.ListCreateAPIView):
    queryset = Feedback.objects.all()
    serializer_class = FeedbackSerializer
    from_class = FeedbackForm
    permission_classes = [FeedbackPermission,]  # I also tried AllowAny

    def form_valid(self, form, FeedbackForm):
        obj = form.save(commit=False)  # I also tried self.obj = ...
        obj.author = self.request.user  # I also  tried self.obj.author = ...
        obj.save()   # I also  tried self.obj.save()
        return super().form_valid(form)

但是在第二次尝试（使用表单）时，作者字段仍然为空。

Answer 1

ListCreateAPIView没有方法form_valid ，看看这个

在您的class FeedbackListView中，您需要执行以下操作：

class FeedbackListView(generics.ListCreateAPIView):
    queryset = Feedback.objects.all()
    serializer_class = FeedbackSerializer

    def perform_create(self, serializer):
        # The request user is set as author automatically.
        serializer.save(author=self.request.user)