编写一个正则表达式来提取一个遵循模式的单词

Question

我有一列包含如下数据。 从中我需要提取批准后的 1 个词，批准者是，批准来自等。关键字“批准”之后的第一个词/名称。 批准应该不区分大小写。

前任 -

第 1 行 - 事件 12345，问题是某某，解决方案是某某。票已被thors批准

第 2 行 - 事件 12900，问题是某某，解决方案是某某。 批准人是：万达倡导者工作朱莉

第 3 行 - 事件 125790，问题是某某，解决方案是某某。 票得到了蜘蛛侠的批准，关闭

第 4 行 - 事件 125790，问题是某某，解决方案是某某。 票是由铁人批准的，等等等等

我试图做 \bApprov*\b([\w][A-Za-z]{4-7}) - 但它不工作

Answer 1

这是一个与您的解决方案非常相似的解决方案，我希望它对您有用。 至少对于这种特殊情况，它会返回您需要的输出：

import regex as re

string = """row 1- incident 12345, issue is so and so, solution is so and so.Ticket was approved by thors

row 2-incident 12900, issue is so and so, solution is so and so. approver is : Wanda Advocate worked julie

row 3-incident 125790, issue is so and so, solution is so and so. Ticket was got approval from- spiderman, closing

row 4-incident 125790, issue is so and so, solution is so and so. Ticket was approved by- ironman, blah blah"""

for row in string.split("\n"):
    if row.startswith("row"):
        m = re.search(r"(?i)(?<=approv[A-Z\s\-\:]+)[A-Z]{5,}", row)
        print(m.group(0))

输出：

thors
Wanda
spiderman
ironman

Answer 2

你想用python实现这个吗？ 如果是这样，下面的代码可能会有所帮助。

代码：

    rows = ['incident 12345, issue is so and so, solution is so and so.Ticket was approved by Thors'
            , 'incident 12900, issue is so and so, solution is so and so. approver is : Wanda Advocate worked julie'
            , 'incident 125790, issue is so and so, solution is so and so. Ticket was got approval from- spiderman, closing'
            , 'incident 125790, issue is so and so, solution is so and so. Ticket was approved by- ironman, blah blah']

    for row in rows:
        clean_row = row.translate({ord(x): None for x in ',.;:[]()-'})
        split_row = clean_row.lower().split('approv')[-1].split()[2]
        print(split_row)

输出：

    thors
    wanda
    spiderman
    ironman
    

Answer 3

使用这个回调函数可以解决这个问题。

txt.replace(/(?<=[a-z0-9]+)\s+[\:\-]/gi, x => x.trim()).match(/(?<=(approv)[az]+\s)[az\s\-\:]+/gi).join().split(' ')[1]

解释：

1. 我正在使用txt.replace(/(?<=[a-z0-9]+)\s+[\:\-]/gi, x => x.trim()) ，因为在 2nd 有一些输入问题输入字符串： row 2-incident 12900, issue is so and so, solution is so and so. approver is : Wanda Advocate worked julie row 2-incident 12900, issue is so and so, solution is so and so. approver is : Wanda Advocate worked julie 。 在 'approver is' 和 ':' 之间添加额外的空格
2. 正则表达式： txt.match(/(?<=(approv)[az]+\s)[az\s\-\:]+/gi).join().split(' ')[1] 。 然后在“approv*”关键字之后找到剩余的单词并打印第二个单词。

代码：

var ar = [`row 1- incident 12345, issue is so and so, solution is so and so.Ticket was approved by thors`,
`row 2-incident 12900, issue is so and so, solution is so and so. approver is : Wanda Advocate worked julie`,
`row 3-incident 125790, issue is so and so, solution is so and so. Ticket was got approval from- spiderman, closing`,
`row 4-incident 125790, issue is so and so, solution is so and so. Ticket was approved by- ironman, blah blah`]

ar.forEach(txt => {
  console.log(txt.replace(/(?<=[a-z0-9]+)\s+[\:\-]/gi, x => x.trim()).match(/(?<=(approv)[a-z]+\s)[a-z\s\-\:]+/gi).join().split(' ')[1]);
})

输出：

thors
Wanda
spiderman
ironman