[英]filter an object of an array of an object
Objects:[
{id:'a',
owner: 'b',
products:[{productId:'a1',name:'b1'},{productId:'a2',name:'b2'}]
date: '2-2'},
{id:'e',
owner: 'f',
products:[{productId:'a3',name:'b3'},{productId:'a4',name:'b4'}]
date: '1-1'}
]
在上面的示例中,如何通过 name:'b3' 的值获取第二个对象? 名称是产品数组的属性,产品是对象数组的属性。 如果有人可以帮助我,我将不胜感激。
要根据产品列表的“名称”属性搜索项目,您可以执行以下操作:
const Objects = [ {id:'a', owner: 'b', products:[{productId:'a1',name:'b1'},{productId:'a2',name:'b2'}], date: '2-2'}, {id:'e', owner: 'f', products:[{productId:'a3',name:'b3'},{productId:'a4',name:'b4'}], date: '1-1' } ] const hasProductsByName = (products) => { return products.some(product => product.name == searchValue); } const searchValue = "b3"; const result = Objects.filter(obj => hasProductsByName(obj.products)); console.log(result);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.