[英]filter an object of an array of an object
Objects:[
{id:'a',
owner: 'b',
products:[{productId:'a1',name:'b1'},{productId:'a2',name:'b2'}]
date: '2-2'},
{id:'e',
owner: 'f',
products:[{productId:'a3',name:'b3'},{productId:'a4',name:'b4'}]
date: '1-1'}
]
在上面的示例中,如何通過 name:'b3' 的值獲取第二個對象? 名稱是產品數組的屬性,產品是對象數組的屬性。 如果有人可以幫助我,我將不勝感激。
要根據產品列表的“名稱”屬性搜索項目,您可以執行以下操作:
const Objects = [ {id:'a', owner: 'b', products:[{productId:'a1',name:'b1'},{productId:'a2',name:'b2'}], date: '2-2'}, {id:'e', owner: 'f', products:[{productId:'a3',name:'b3'},{productId:'a4',name:'b4'}], date: '1-1' } ] const hasProductsByName = (products) => { return products.some(product => product.name == searchValue); } const searchValue = "b3"; const result = Objects.filter(obj => hasProductsByName(obj.products)); console.log(result);
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