虽然循环没有返回它的条件

Question

attempts=0

number=int(input("Enter a number from a range of 0 to a 100: "))

while number<0 and number>100:
    attempts=attempts+1
    number=int(input("Number is invalid. Please enter a number from a range of 0 to a 100: "))

attempts=attempts+1    
print("Number of attempts for inputting a valid number: ", attempts)

我正在编写一个程序，其中输入的数字在 0 到 100 的范围内进行验证。如果它无效，则该数字将被拒绝，并会显示提示以重新输入数字。 然后我需要 output 尝试输入有效数字的次数。

至此，当输入大于 0 小于 100 的 integer 时，程序运行正常。 如果输入 integer，假设输入 -50，则应显示提示，然后需要重新输入数字 - 但我的 while 循环没有返回其条件，它会显示 output：

Enter a number from a range of 0 to a 100: -50 
Number of attempts for inputting a valid number:  1

Answer 1

我认为在while循环中，条件应该是or不是and 。

attempts=0

number=int(input("Enter a number from a range of 0 to a 100: "))

while number<0 or number>100:
    attempts=attempts+1
    number=int(input("Number is invalid. Please enter a number from a range of 0 to a 100: "))

attempts=attempts+1    
print("Number of attempts for inputting a valid number: ", attempts)

Answer 2

您应该使用“或”来代替“和”：

attempts=0

number=int(input("Enter a number from a range of 0 to a 100: "))

while number<0 or number>100:
    attempts=attempts+1
    number=int(input("Number is invalid. Please enter a number from a range of 0 to a 100: "))

attempts=attempts+1
print("Number of attempts for inputting a valid number: ", attempts)

Answer 3

这是我的建议：

attempts=0

number=int(input("Enter a number from a range of 0 to a 100: "))

while number not in range(0, 101):
    attempts=attempts+1
    number=int(input("Number is invalid. Please enter a number from a range of 0 to a 100: "))

attempts=attempts+1    
print("Number of attempts for inputting a valid number: ", attempts)

结果：

Enter a number from a range of 0 to a 100: -1
Number is invalid. Please enter a number from a range of 0 to a 100: 101
Number is invalid. Please enter a number from a range of 0 to a 100: 100
Number of attempts for inputting a valid number:  3
Enter a number from a range of 0 to a 100: 0
Number of attempts for inputting a valid number:  1

Answer 4

错误在这里，而number<0 and number>100: or意味着至少一个条件是正确的，但意味着所有条件都是正确的。 现在看看条件 没有数字可以同时满足您的条件，例如less than 0 and greater than 100 at a sametime. 因此您可以使用或操作，因此条件之一满足要求然后执行代码。

attempts=0
invalid_attempts=0
number=int(input("Enter a number from a range of 0 to a 100: "))
while number<0 or number>100:
    
    number=int(input("Number is invalid. Please enter a number from a range of 0 to a 100: "))
    invalid_attempts+=1
attempts=attempts+1    
print("Number of attempts for inputting a valid number: ", attempts)
print("Number of attempts for inputting a Invalid number: ", invalid_attempts)