如何使用 firebase 9 push 来实现这一点？

Question

我切换到 firebase 9 并希望实现以下

customers
   -MomOdRNzkqr9vDk_MmE:"ptwXJ7JRAASFgd3KoS2fQyQhyV613"
   -Myb3b_2W-7FTlsZvXCO:"QZOQ43DGYwfu4djlZ5EjEVksOr53"

我正在尝试以下

const customerSelectedRef = ref(db,`/serviceProvider/${user1.uid}/moneyCollector/customers`);
const customerSelectedRefPush = push(customerSelectedRef);
set(customerSelectedRefPush, customerSelected); // not wanted to use {customerSelected} which gives key value pair under push id

怎么能直接为push id增值？

旧方法是

  firebase
    .database()
    .ref(`/serviceProvider/${user1.uid}/moneyCollector/customers`)
    .push(customerSelected)
    .then(() => {
      console.log("Data set.moneyCollector cutomer added");
      checkdubArray = [];
    });

其中 push id 作为customerSelected的键，我尝试在 firebase 9 中获得相同的结果。不想要我标记为交叉的结果

Answer 1

您可以将字符串值与DatabaseReference一起直接在push()中传递，如下所示：

const customerSelectedRef = ref(db,`/service/${user1.uid}/Collector/customers`);

await push(customerSelectedRef , "string_value") // Not object

结果将是：