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[英]python How can I stop an infinite while loop and continue with rest of code?
[英]How can I get python to count the amount of characters of a word and then continue or stop the code?
对于作业,我需要使用“len”function 来确定在“original_word”中输入了多少个字符。 如果单词大于或小于五个字符,程序需要“exit()”
我怎样才能做到这一点?
original_word: str = input("Enter a 5-character word: ")
character_one: str = input("Enter a single character: ")
print("Searching for " + character_one + " in " + original_word)
if character_one == original_word[0]:
print(character_one + " found at index 0")
if character_one == original_word[1]:
print(character_one + " found at index 1")
if character_one == original_word[2]:
print(character_one + " found at index 2")
if character_one == original_word[3]:
print(character_one + " found at index 3")
if character_one == original_word[4]:
print(character_one + " found at index 4")
counter = 0
for c in original_word:
if c == character_one:
counter += 1
if counter == 2:
print(counter, " instances of " + character_one + " found in " + original_word)
if counter == 1:
print(counter, " instance of " + character_one + " found in " + original_word)
if counter == 0:
print("No instances of " + character_one + " found in " + original_word)
一种可能的方法是制作function,如果您的单词长度为5,则完成代码,否则返回短语“长度不是5,再试一次”
你也可以把代码写得更短一些。 这是示例:
def main(original_word, character_one):
if len(original_word) == 5:
temp_word = original_word
print(f"Searching for {character_one} in {original_word}")
while True:
if character_one in temp_word:
index = temp_word.find(character_one)
print(f"{character_one} found at index {index}")
temp_word = temp_word[:index] + ' ' + temp_word[index + 1:]
else:
break
counter = original_word.count(character_one)
print(f"{counter} instances of {character_one} found in {original_word}")
else:
return "The input word is greater or less than 5 characters! Please, try again."
original_word: str = input("Enter a 5-character word: ")
character_one: str = input("Enter a single character: ")
if __name__ == "__main__":
main(original_word, character_one)
第一个修改是 f-string。 这是连接而不是汇总变量和字符串的最流行和最方便的未来。
第二个修改是检查字符是否在单词中,而不是使用大量的 if 语句。 很容易通过以下方式检查:
if x in y:
在字符串中查找字符索引的方法是方法find 。 样本:
string.find(substring) # It returns the index of substring in string
最后一个是方法计数器,它返回字符串中 ZE83AED3DDF4667DEC0DAAAACB2BB3BE0BZ 的数量。 这是示例:
string.count(substring) # It returns amount of substring in your string
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