如何从基础 class 获取派生 class 的名称

Question

我可以得到一个基础 class 的名称，如下所示：

>>> class Base(object):
...     pass
...
>>> class Derived(Base):
...     def print_base(self):
...         for base in self.__class__.__bases__:
...             print base.__name__
...
>>> foo = Derived()
>>> foo.print_base()
Base

在此示例中，我如何执行相反的操作并从Base中的 function 中获取Derived的名称？ 例如：

>>> class Base(object):
...     def print_derived(self):
...         [pseudocode: return Derived class name]
...
>>> class Derived(Base):
...     pass
...
>>> bar = Derived()
>>> bar.print_derived()
Derived

我显然可以在Derived中打印self.__class__.__name___但我有很多单元测试继承Base作为 mixin，我想跟踪哪个 class 从对Base mixin 的一次调整中调用它。

Answer 1

您只需要在Base方法中打印self.__class__ ：

>>> class Base(object):
...     def print_derived(self):
...         print(self.__class__.__name__)
...
>>> class Derived(Base):
...     pass
>>> d = Derived()
>>> d.print_derived()
Derived