根据行号拆分字符串和 select

Question

通过用“。”分隔，我有一个具有多个 id 的字符串。 如以下所说的

'4400028285.4400043238.4400051619.4400052460.4400074441.4400124290.4400131680.4400137443 4400140030.4400141964.4400143906.4400143906.4400144145.4400149146'

试图解析字符串并获取使用PARSENAME()解析字符串的单个记录，但它允许获取四到五行

正如我在下面编码的

PARSENAME('4400028285.4400043238.4400051619.4400052460.4400074441.4400124290.4400131680.4400137443 4400140030.4400141964.4400143906.4400143906.4400144145.4400149146', 6)

我们可以使用任何其他 function 根据行号返回行和 select 吗？

Answer 1

请尝试以下查询，

DECLARE @T VARCHAR(200) = '4400028285.4400043238.4400051619.4400052460.4400074441.4400124290.4400131680.4400137443 4400140030.4400141964.4400143906.4400143906.4400144145.4400149146'


SELECT * FROM (
SELECT ROW_NUMBER() OVER (ORDER BY Value) AS RowNum
,Value
FROM string_split(@T,'.')) A

Answer 2

您可以为此使用json解析

declare @string varchar(500)='4400028285.4400043238.4400051619.4400052460.4400074441.4400124290.4400131680.4400137443.4400140030.4400141964.4400143906.4400143906.4400144145.4400149146'

select [value]
from OpenJson(Concat('["', replace(@string, '.', '", "'), '"]'))
order by Convert(int, [key])