如何将学生 Function 的值返回到 Main，以便我可以将它们用于显示 Function？

Question

程序：

#include <iostream>
#include <string>
#include <iomanip>

using namespace std;

//Structure
struct Student{
    string name;
    int pMark;
    int eMark;
    double avg;
    string result;
};

//Functions
Student info(int arrSize, Student arrStudent[10]);
void display(int arrSize, Student arrStudents[10]);

//Main program
int main() {
    Student arrStudents[10];
    int arrSize;

    cout << "How many Students are there(max 10): ";
    cin >> arrSize;

    info(arrSize, arrStudents);
    display(arrSize, arrStudents);

    return 0;
}

//Student Function
Student info(int arrSize, Student arrStudent[10]){
    int counter = 0;
    while(counter < arrSize){
        cout << "\nStudent " << (counter + 1) << " info:";
        cout << "\nEnter the name: ";
        cin >> arrStudent[counter].name;
        cout << "Enter the participation mark: ";
        cin >> arrStudent[counter].pMark;
        cout << "Enter the exam mark: ";
        cin >> arrStudent[counter].eMark;

        arrStudent[counter].avg = (arrStudent[counter].pMark + arrStudent[counter].eMark) / 2.00;

        if (arrStudent[counter].avg >= 50) {
            arrStudent[counter].result = "Pass";
        }
        else {
            arrStudent[counter].result = "Fail";
        }
        counter++;
    }

    return arrStudent;//(Return Array)?
}

//Display Function
void display(int arrSize, Student arrStudents[10]) {
    cout << endl << "Name\t\t Average\t\t Result" << endl;

    for (int counter = 0; counter < arrSize; counter++) { 
        cout << arrStudents[counter].name << "\t\t"
             << fixed << setprecision(2) 
             << arrStudents[counter].avg << "\t\t\t"
             << arrStudents[counter].result << endl;
    }
}

我尝试使用 function 这样，但我不确定它是否正确？

//Student Function
Student info(int arrSize, Student arrStudent[10]){
    int counter = 0;
    while (counter < arrSize) {
        cout << "\nStudent " << (counter + 1) << " info:";
        cout << "\nEnter the name: ";
        cin >> arrStudent[counter].name;
        cout << "Enter the participation mark: ";
        cin >> arrStudent[counter].pMark;
        cout << "Enter the exam mark: ";
        cin >> arrStudent[counter].eMark;

        arrStudent[counter].avg = (arrStudent[counter].pMark + arrStudent[counter].eMark) / 2.00;

        if (arrStudent[counter].avg >= 50) {
            arrStudent[counter].result = "Pass";
        }
        else {
            arrStudent[counter].result = "Fail";
        }
        counter++;
    }
    return arrStudent[arrSize];
}

我是编码新手（在大学里），所以我们仍然需要了解向量、指针和引用。 这就是为什么我没有尝试任何其他方法。 如果可以通过避免这些方法来解决它，我将非常感谢这些解决方案。

Answer 1

您正在按值传递数组的值，您应该通过引用传递它们，因此您应该使用指针，

示例 function：

Student info(int arrSize, int *arrStudent)