如何访问列表中字典中的条件项

Question

empty_list=[] employee = [{ "name" : "Nauman", "age" : 27, "Salary": 29000 }, { "name": "Bilal", "age": 26, "Salary": 27000 }, { "name": "Ali", "age": 19, "Salary": 22000 }, { "name": "Usman", "age": 28, "Salary": 34000 }, { "name": "Usama", "age": 14, "Salary": 24000 } ] def function(employee): for value in employee: if employee.my_dict(["age"])>25 and employee.my_dict(["salary"])>25000: empty_list.append(employee) print(empty_list)

Answer 1

这有助于：

def function(employee):
    for value in employee:
        if value["age"] > 25 and value["Salary"] > 25000:
            empty_list.append(value)

function(employee)

但最好用 return 来做：

def function(listof:list)->list:
    empty_list = []
    for value in listof:
        if value["age"] > 25 and value["Salary"] > 25000:
            empty_list.append(value)
    return empty_list

print(function(employee))

Answer 2

您可以按如下方式更正和改进您的代码：

1. 将您的数据作为参数传递给您的 function，而不是尝试直接访问全局变量。
2. 从您的员工列表中访问每个员工，然后使用相关键访问所需的数据，例如employee['age']
3. 您的 function 可以返回包含满足指定条件的员工的结果。 然后，您可以在需要时调用 function。

这是遵循上述更正/建议的示例解决方案：

data = [
    {
        "name" : "Nauman",
        "age" : 27,
        "salary": 29000
    },
    {
        "name": "Bilal",
        "age": 26,
        "salary": 27000
    },
    {
        "name": "Ali",
        "age": 19,
        "salary": 22000
    },
    {
        "name": "Usman",
        "age": 28,
        "salary": 34000
    },
    {
        "name": "Usama",
        "age": 14,
        "salary": 24000
    }]


def retrieve_desired_employees(employees):
    result = []
    for employee in employees:
        if employee['age'] > 25 and employee['salary'] > 25000:
            result.append(employee)
    return result


result = retrieve_desired_employees(data)
print(result)

Answer 3

def get_empty_list(employees):
    return [employee for employee in employees if employee["age"]>25 and employee["Salary"]>25000]