如何使用 python 程序从这个文本文件中读取正确的行，然后通过填写从 .txt 文件中提取的数据来创建一个 .py 文件？

Question

要读取的文本文件（真实的包含更多的数字），名为number_info.txt

veinti tres
23

veinti dos
22

veinti uno
21

veinte
20

tres
3

dos
2

uno
1

这是代码（我需要帮助）

import re

def auto_coding_text_to_number():

    with open('number_info.txt', 'r') as f:

        #lines 0, 3, 6, 9, 12, 15, 18, ...
        coloquial_numbers = []

        #lines 0+1, 3+1, 6+1, 9+1, 12+1, 15+1, 18+1, ... 
        symbolic_numbers = []


    n = 0
    with open('number_to_text.py', 'w') as f:
        f.write('import re\n\ndef number_to_text_func(input_text):\n')
       
        #write replacement lines based on regex
        if(" " in coloquial_numbers[n]):
            #for example write this line:   "    input_text = re.sub(r"veinti[\s|-|]*tres", "23", input_text)"
        
        if not (" " in coloquial_numbers[n]):
            #for example write this line:   "    input_text = re.sub("tres", "3", input_text)"
            
        f.write("    return(input_text)\n    input_text = str(input())\n 
   print(number_to_text_func(input_text))")

        n = n + 1

auto_coding_text_to_number()

这是正确的文件，名为number_to_text.py ，应该由其他脚本编写

import re

def number_to_text_func(input_text):
    input_text = re.sub(r"veinti[\s|-|]*tres", "23", input_text)
    input_text = re.sub(r"veinti[\s|-|]*dos", "22", input_text)
    input_text = re.sub(r"veinti[\s|-|]*uno", "21", input_text)
    input_text = re.sub("tres", "3", input_text)
    input_text = re.sub("dos", "2", input_text)
    input_text = re.sub("uno", "1", input_text)

    return(input_text)

input_text = str(input())
print(number_to_text_func(input_text))

---

编辑：

.txt 文件中的行结构如下

"veinti tres"  <---- line 0
"23"           <---- line 1
"veinti dos"   <---- line 2
"22"           <---- line 3
"veinti uno"   <---- line 4
"21"           <---- line 5
"veinte"       <---- line 6
"20"           <---- line 7
"tres"         <---- line 8
"3"            <---- line 9

然后我建议将它们分成 2 组并将它们存储在 2 个列表中

#lines 0, 3, 6, 9, 12, 15, 18, ...
coloquial_numbers = ["veinti tres", "veinti dos", "veinti uno", "veinte", "tres"]

#lines 0+1, 3+1, 6+1, 9+1, 12+1, 15+1, 18+1, ...
symbolic_numbers = ["23", "22", "21", "20". "3"]


body_template = """    input_text = re.sub(r"{}", "{}", input_text)\n"""

然后 function 的主体应该是这样的结构

input_text = re.sub(coloquial_numbers[n].replace(' ', '[\s|-|]'), symbolic_numbers[n], input_text)

在 output 文件的 function 正文中得到类似的东西

def number_to_text(input_text):
    input_text = re.sub(r"veinti[\s|-|]*tres", "23", input_text)
    input_text = re.sub(r"veinti[\s|-|]*dos", "22", input_text)
    input_text = re.sub(r"veinti[\s|-|]*uno", "21", input_text)
    input_text = re.sub("tres", "3", input_text)

    return(input_text)

Answer 1

为了简单起见，我省略了读/写步骤。 没有给出指定元 function 主体的规则，所以我做了一个猜测。

import re 

# body-component of the meta-code
body_template = """    input_text = re.sub(r"{}", "{}", input_text)\n"""

# read from file
with open('number_info.txt', 'r') as fd:
    text = fd.read()

# update body
body = ''
for n_text, n in re.findall(r'\n*([a-z\s]+)\n(\d+)', text):
    body += body_template.format(n_text.replace(' ', '[\s|-|]'), n)

# other components of the meta-code
header = """import re

def number_to_text_func(input_text):
"""

tail = """\n    return(input_text)

input_text = str(input())
print(number_to_text_func(input_text))"""

# merge together texts to be saved to file
meta_code = header + body + tail
print(meta_code)

Output（ number_to_text.py的内容）

import re

def number_to_text_func(input_text):
    input_text = re.sub(r"treinta[\s|-|]y[\s|-|]uno", "31", input_text) # <-
    input_text = re.sub(r"veinti[\s|-|]tres", "23", input_text)
    input_text = re.sub(r"veinti[\s|-|]dos", "22", input_text)
    input_text = re.sub(r"veinti[\s|-|]uno", "21", input_text)
    input_text = re.sub(r"veinte", "20", input_text)
    input_text = re.sub(r"tres", "3", input_text)
    input_text = re.sub(r"dos", "2", input_text)
    input_text = re.sub(r"uno", "1", input_text)

    return(input_text)

input_text = str(input())
print(number_to_text_func(input_text))

---

来自评论：每行读取文件，没有正则表达式

with open('number_info.txt', 'r') as fd:
    lines = fd.read().split()

symbolic_numbers, coloquial_numbers = [], []
for i, line in enumerate(lines):
    if i % 3 == 0:
        coloquial_numbers.append(line)
    elif i % 3 == 1:
        symbolic_numbers.append(line)