[英]How to sort String List by newest in dart
我有String List
,每个元素包含userId+DateTime
List<String> = [
'9DWXpF6V4vN8oxqvsHKnOBg2Rz2022-09-14 00:07:52.707',
'8jk9wQ0U5gNyekzNz84SDb0jDTf12022-09-12 00:07:52.704',
'0RMRZFCifmSe2CGW6k7Rvq8gvni2022-09-13 00:07:52.704'
]
现在我需要根据User Id
旁边的DateTime
时间从最新到最旧对列表进行排序
所以我正在尝试 output 看起来像下面
List<String> = [
'9DWXpF6V4vN8oxqvsHKnOBg2Rz2022-09-14 00:07:52.707',
'0RMRZFCifmSe2CGW6k7Rvq8gvni2022-09-13 00:07:52.704'
'8jk9wQ0U5gNyekzNz84SDb0jDTf12022-09-12 00:07:52.704',
]
注意:在我的示例中,我确实关心日期只是为了解释我的用例,但我需要根据最近的日期和时间对列表进行排序,而不仅仅是日期
我该如何实施?
尝试这个:
RegExp regex = RegExp(r'\d{4}-\d{2}-\d{2}\s+\d{2}:\d{2}:\d{2}\.\d+$');
list.sort(
(first, second) {
String? firstDateString = regex.firstMatch(first)?.group(0);
if (firstDateString == null) {
throw ArgumentError("$firstDateString does not contain any date");
}
String? secondDateString = regex.firstMatch(second)?.group(0);
if (secondDateString == null) {
throw ArgumentError("$secondDateString does not contain any date");
}
DateTime firstDate = DateTime.parse(firstDateString);
DateTime secondDate = DateTime.parse(secondDateString);
return secondDate.compareTo(firstDate);
}
);
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