i have String List
, per element contains userId+DateTime
List<String> = [
'9DWXpF6V4vN8oxqvsHKnOBg2Rz2022-09-14 00:07:52.707',
'8jk9wQ0U5gNyekzNz84SDb0jDTf12022-09-12 00:07:52.704',
'0RMRZFCifmSe2CGW6k7Rvq8gvni2022-09-13 00:07:52.704'
]
now i need to sort the list from newest to oldest depends of that DateTime
next to User Id
so i am trying the output look like following
List<String> = [
'9DWXpF6V4vN8oxqvsHKnOBg2Rz2022-09-14 00:07:52.707',
'0RMRZFCifmSe2CGW6k7Rvq8gvni2022-09-13 00:07:52.704'
'8jk9wQ0U5gNyekzNz84SDb0jDTf12022-09-12 00:07:52.704',
]
Note: in my example i did care in day date just to explain my use case but i need to sort my list According to the most recent date and time , not only day date
How can i implement this?
Try this:
RegExp regex = RegExp(r'\d{4}-\d{2}-\d{2}\s+\d{2}:\d{2}:\d{2}\.\d+$');
list.sort(
(first, second) {
String? firstDateString = regex.firstMatch(first)?.group(0);
if (firstDateString == null) {
throw ArgumentError("$firstDateString does not contain any date");
}
String? secondDateString = regex.firstMatch(second)?.group(0);
if (secondDateString == null) {
throw ArgumentError("$secondDateString does not contain any date");
}
DateTime firstDate = DateTime.parse(firstDateString);
DateTime secondDate = DateTime.parse(secondDateString);
return secondDate.compareTo(firstDate);
}
);
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