[英]Quick checking if element exists with Python Selenium
我找到了关于检查元素可见性的答案。 我对这个答案的问题是,它永远不会返回“找不到元素”。 不仅。 给出错误消息需要很长时间(如下)。
from selenium import webdriver
from selenium.webdriver.common.by import By
driver = webdriver.Firefox()
driver.get('http://www.google.com')
element = driver.find_element(By.XPATH, '/html/body/div[1]/div[1]/a[2]') #this element exists
if element.is_displayed():
print("Element found")
else:
print("Element not found")
hidden_element = driver.find_element(By.XPATH,'/html/body/div[1]/div[1]/a[20]') #this one doesn't exist
if hidden_element.is_displayed():
print("Element found")
else:
print("Element not found")
我需要更高效的东西并返回 False 或其他错误消息:
RemoteError@chrome://remote/content/shared/RemoteError.jsm:12:1 WebDriverError@chrome://remote/content/shared/webdriver/Errors.jsm:192:5 NoSuchElementError@chrome://remote/content/ shared/webdriver/Errors.jsm:404:5 element.find/</<@chrome://remote/content/marionette/element.js:291:16
您可以使用driver.find_elements
方法代替driver.find_element
。
像这样的东西:
if driver.find_elements(By.XPATH,'/html/body/div[1]/div[1]/a[20]'):
print("Element found")
else:
print("Element not found")
driver.find_elements
将返回与传递的定位器匹配的 web 元素列表。 In case such elements found it will return non-empty list interpreted by Python as a Boolean True
while if no matches found it will give you an empty list interpreted by Python as a Boolean False
.
为了减少这里花费的时间,您可以将implicitly_wait
定义为一些短值,例如 1 或 2 秒,如下所示:
driver.implicitly_wait(2)
UPD
如果您想检查元素显示状态,您可以按索引从列表中获取元素,如下所示:
elements = driver.find_elements(By.XPATH,'/html/body/div[1]/div[1]/a[20]')
if elements:
print("Element found")
if elements[0].is_displayed():
print("Element is also displayed")
else:
print("Element not found")
您可以检查元素的长度
hidden_element = driver.find_elements(By.XPATH,'/html/body/div[1]/div[1]/a[20]') #this one doesn't exist
if len(hidden_element)>0:
print("Element found")
else:
print("Element not found"
)
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