繁体   English   中英

get_item dynamodb with if else 条件如果项目匹配

[英]get_item dynamodb with if else condition if item has a match


def main():
    alias = "jen"
    ddb = boto3.client("dynamodb")

    get_ddb_item = ddb.get_item(TableName="testtable", Key={"employee": {"S": alias}})

    item = get_ddb_item["Item"]
    print(item)

    if item == alias:
         print(f"{alias} is an employee")

    else:
         print(f"{alias} is not an active employee")

testtable上唯一的内容是PK: employee item: "jen" I am expecting an out put of jen is an employee

这是我上面的代码,它给了我相反的jen is not an active employee获得预期的 output 的正确方法是什么?

你得到这个是因为item != 'jen'

if item['employee']['S'] == alias:
     print(f"{alias} is an employee")

else:
     print(f"{alias} is not an active employee")

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM